nicolas
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 Dec18 awarded Notable Question Nov25 answered Largest “leap-to-generality” in math history? Nov15 revised right inverse and supplement of kernel in a banach added 2 characters in body Nov15 comment right inverse and supplement of kernel in a banach oh yes, sorry. I'll fix that Nov15 comment right inverse and supplement of kernel in a banach it sounds like a more elegant formulation. Nov15 revised right inverse and supplement of kernel in a banach edited title Nov15 asked right inverse and supplement of kernel in a banach Nov13 comment If $f$ is continuous at $a$, is it continuous in some open interval around $a$? @Kaz what do you mean ? Nov12 comment How to show that $(\operatorname{Im}{A})^⊥ = \ker(A^⊤)$, $\operatorname{Im}{(A^⊤)}= (\ker A)^⊥$? in infinite dimension, one only has $closure(Im A^T) \subset {ker A}^\perp$ Nov11 comment show: $\overline{\overline X} = \overline X$ this is the way to prove it. dealing with epsilon is overkill for this Nov11 comment How to show that $(\operatorname{Im}{A})^⊥ = \ker(A^⊤)$, $\operatorname{Im}{(A^⊤)}= (\ker A)^⊥$? @Timbuc he refers to another question I think Nov11 comment How to show that $(\operatorname{Im}{A})^⊥ = \ker(A^⊤)$, $\operatorname{Im}{(A^⊤)}= (\ker A)^⊥$? @qexi this is another question. and one for which you might be surprised by the answer :) Nov11 comment How to show that $(\operatorname{Im}{A})^⊥ = \ker(A^⊤)$, $\operatorname{Im}{(A^⊤)}= (\ker A)^⊥$? this is not always true in infinite dimension I think btw Nov11 answered How to show that $(\operatorname{Im}{A})^⊥ = \ker(A^⊤)$, $\operatorname{Im}{(A^⊤)}= (\ker A)^⊥$? Nov10 comment Can't argue with success? Looking for “bad math” that “gets away with it” That was a test by the student to see if teacher reads the proof Nov10 comment Can't argue with success? Looking for “bad math” that “gets away with it” @joriki if only mathematics was using "expressions", binders, higher order functions, and other rigorous CS notations (de brujin), the work would be a better place.. how many bad conceptual math have been produced by wrong notations... Nov10 comment Can't argue with success? Looking for “bad math” that “gets away with it” @Squirtle I just did Nov10 comment Can't argue with success? Looking for “bad math” that “gets away with it” @GrumpyParsnip that counts as luck in my book Nov8 awarded Yearling Oct30 comment A finite group of even order has an odd number of elements of order 2 you know what, that was annoying. so easy after seeing it it is fuming.