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Jul
21
comment Prove that this function is measurable
Can you please provide more details in the first point of your argument? Still I cannot follow you completely even though you are convincing me you are right... Moreover, I can't see what is $j$ in the formula.. Of course later i will accept your answer.. Thank you Davide
Jul
21
asked Prove that this function is measurable
Jun
11
accepted $A$ has measure $0$
Jun
11
comment $A$ has measure $0$
you mean... $\sin(n_kx)\to\pm\frac{1}{\sqrt2}$?
Jun
11
comment $A$ has measure $0$
but what if, for example, $n_k=4k+1$ and $x=\frac\pi2$? In this case the limit exists and it is constantly $1$ so I cannot claim that if the limit exists then it is $0$. I don't get your point sorry...
Jun
11
asked $A$ has measure $0$
Jun
3
accepted The solutions are bounded on $[0,+\infty)$
Jun
3
comment The solutions are bounded on $[0,+\infty)$
@Giuseppe.... lol.. I have to remember just trigonometric identities it seems... :) to expiate it i will write down a thousand times $$\sin(t-\xi)=\sin(t)\cos(\xi)-\cos(t)\sin(\xi).$$ Grazie btw
Jun
1
accepted Stability of the origin as parameter varies
Jun
1
asked The solutions are bounded on $[0,+\infty)$
May
5
accepted Prove that the space is not complete
May
5
asked Prove that the space is not complete
May
2
awarded  Editor
May
2
revised Stability of the origin as parameter varies
added 339 characters in body
May
1
comment Stability of the origin as parameter varies
I know how to linearize the system around the origin, an then how to solve point a). Point b) however is escaping my mind. In particular, even if it is quite embarassing to say, i don't understand what globally means in tht context. So, yes, point b) is my main issue to deal with.
May
1
asked Stability of the origin as parameter varies
Apr
30
accepted Prove that there are no analytic function satisfying this property
Apr
30
asked Prove that there are no analytic function satisfying this property
Apr
29
accepted Monotone sequence bounded in $L^2([0,1])$ strongly converges
Apr
29
asked Monotone sequence bounded in $L^2([0,1])$ strongly converges