guido giuliani
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 Jul 21 comment Prove that this function is measurable Can you please provide more details in the first point of your argument? Still I cannot follow you completely even though you are convincing me you are right... Moreover, I can't see what is $j$ in the formula.. Of course later i will accept your answer.. Thank you Davide Jul 21 asked Prove that this function is measurable Jun 11 accepted $A$ has measure $0$ Jun 11 comment $A$ has measure $0$ you mean... $\sin(n_kx)\to\pm\frac{1}{\sqrt2}$? Jun 11 comment $A$ has measure $0$ but what if, for example, $n_k=4k+1$ and $x=\frac\pi2$? In this case the limit exists and it is constantly $1$ so I cannot claim that if the limit exists then it is $0$. I don't get your point sorry... Jun 11 asked $A$ has measure $0$ Jun 3 accepted The solutions are bounded on $[0,+\infty)$ Jun 3 comment The solutions are bounded on $[0,+\infty)$ @Giuseppe.... lol.. I have to remember just trigonometric identities it seems... :) to expiate it i will write down a thousand times $$\sin(t-\xi)=\sin(t)\cos(\xi)-\cos(t)\sin(\xi).$$ Grazie btw Jun 1 accepted Stability of the origin as parameter varies Jun 1 asked The solutions are bounded on $[0,+\infty)$ May 5 accepted Prove that the space is not complete May 5 asked Prove that the space is not complete May 2 awarded Editor May 2 revised Stability of the origin as parameter varies added 339 characters in body May 1 comment Stability of the origin as parameter varies I know how to linearize the system around the origin, an then how to solve point a). Point b) however is escaping my mind. In particular, even if it is quite embarassing to say, i don't understand what globally means in tht context. So, yes, point b) is my main issue to deal with. May 1 asked Stability of the origin as parameter varies Apr 30 accepted Prove that there are no analytic function satisfying this property Apr 30 asked Prove that there are no analytic function satisfying this property Apr 29 accepted Monotone sequence bounded in $L^2([0,1])$ strongly converges Apr 29 asked Monotone sequence bounded in $L^2([0,1])$ strongly converges