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  • 32 votes cast
Apr
30
comment Constructor theory distinguishability
Seems like a reasonable idea. I haven't gone back to validate your proof, but it appears sound. Thanks!
Apr
30
accepted Constructor theory distinguishability
Apr
23
revised Constructor theory distinguishability
added 8 characters in body
Feb
24
comment Big-O complexity of iterating over every substring
@Tryss: Thanks, would you be able to explain this a little? In fact, I actually need to add a third nested loop, which iterates j/2 times, so I'm not sure how to extrapolate from your answer to a more general solution.
Feb
24
asked Big-O complexity of iterating over every substring
Feb
20
awarded  Tumbleweed
Feb
13
asked Constructor theory distinguishability
Feb
7
awarded  Popular Question
Sep
24
awarded  Autobiographer
Jul
2
awarded  Curious
Jun
11
accepted How to denote domain and range
Jun
11
asked How to denote domain and range
Mar
18
accepted Enumerating cases for conditional probability
Mar
1
accepted Understanding group presentation as a quotient
Mar
1
comment Understanding group presentation as a quotient
Wow, nice answer, thanks for putting in the time! I'm going to have to put in some time studying it some more to understand it, but I think I was able to follow each step, just haven't quite pulled it all together into a conclusion yet. Also, I think there's a typo in the last paragraph: you have $fef$ listed twice in $\hat{G}$.
Feb
28
asked Understanding group presentation as a quotient
Feb
26
accepted Show that group action is homomorphism to Symmetric group
Feb
26
comment Show that group action is homomorphism to Symmetric group
Oh, ok. So my original formulation for the condition of homomorphism was off. I think it makes sense now, thanks!
Feb
26
comment Show that group action is homomorphism to Symmetric group
Actually, I take that back, $A_g(x)$ is not a permutation of $X$, it's an element of $X$. So how can you compose a permutation/function, $A_g$ with an element of a set, $A_f(x)$?
Feb
26
comment Show that group action is homomorphism to Symmetric group
@SpamIAm: Thanks, but I think you over estimate me. I have the axioms written out as $A(e,x) = x$ for all $x$ (where $e$ is the identity of $G$) and $A(g, A(f,x)) = A(g+f, x)$, but it's still not clear to me why this defined a homomorphism.