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| bio | website | wallenborn.net |
|---|---|---|
| location | Bonn, Germany | |
| age | ||
| visits | member for | 1 year, 2 months |
| seen | 8 hours ago | |
| stats | profile views | 36 |
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Apr 26 |
revised |
Find if a number $n$ is a primitive root of $p$ added tex code |
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Apr 26 |
suggested | suggested edit on Find if a number $n$ is a primitive root of $p$ |
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Apr 26 |
revised |
Finding nth degree polynomial functions added argument about degree |
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Apr 26 |
answered | Finding nth degree polynomial functions |
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Apr 16 |
awarded | Enlightened |
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Apr 14 |
awarded | Enthusiast |
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Mar 6 |
revised |
Why doesn't Dirichlet function have a derivative in X=0 made it tex |
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Mar 6 |
suggested | suggested edit on Why doesn't Dirichlet function have a derivative in X=0 |
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Mar 6 |
comment |
Can a vector component contain values that are not from the space's field? I assume that you mean the field of rational numbers $\mathbb Q$ - not any field - ecause you say that $\sqrt{2}$ is not an element of it? |
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Mar 6 |
comment |
what is simplify, of $\sin^{-1}\tanh\theta=?$ I think, you missed an $=$-sign and something on the right hand side of the equation. |
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Mar 1 |
comment |
Bounding the number of nonzero coefficients in a conic combination but how do you make sure that none of the coefficients of this linear combination is less than $0$? |
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Feb 27 |
awarded | Yearling |
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Feb 23 |
awarded | Nice Answer |
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Feb 22 |
accepted | Serre's proof that zeta function is meromorphic |
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Feb 21 |
comment |
Serre's proof that zeta function is meromorphic I don't see how this implies $|\phi_n(s)|\leq\frac{|s|}{n^{x+1}}$ and what it has to do with the derivative. |
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Feb 21 |
asked | Serre's proof that zeta function is meromorphic |
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Feb 21 |
accepted | Set of locations where the Hilbert symbol is not equal to $1$ |
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Feb 15 |
revised |
counterexample for: integral forms that are equivalent as rational forms are also equivalent as integral forms added 10 characters in body |
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Feb 15 |
asked | counterexample for: integral forms that are equivalent as rational forms are also equivalent as integral forms |
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Jan 7 |
comment |
Linear Algebra- independence and dependence When you speak about a vetorspace you always have to say what your "base field" is. That is the set where the scalars come from. In high school we are normally used to the vectorspace $\mathbb{R}^n$ which we normally consider "over the field $\mathbb{R}$", but in general the base field can be everything (for example $\mathbb{F}_2$ or $\mathbb{Q}$) and $V$ does not need to be a power of the field $\mathbb{F}^n$. |
