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6h
asked What is switching rows useful for?
14h
comment How do I express logical connectives with Nand?
@MauroALLEGRANZA You can use $\uparrow, \rightarrow, \downarrow, \leftarrow, \triangle, \times ,\bigcirc, \times, \square, \triangle$ to attack with Akuma's combo on Street Fighter $V$.
15h
revised How do I express logical connectives with Nand?
added 172 characters in body
1d
revised How do I express logical connectives with Nand?
added 170 characters in body
1d
answered How do I express logical connectives with Nand?
2d
reviewed Approve $\frac {1} {ab} + \frac {1} {ac} + \frac {1} {ad} + \frac {1} {bc} + \frac {1} {bd} + \frac {1} {cd}$
Jul
31
asked Why $\lim_{\Delta x\to 0} \cfrac{\int_{x}^{x+\Delta x}f(u) du}{\Delta x}=\cfrac{f(x)\Delta x}{\Delta x}$?
Jul
28
comment What's the meaning of the $R(f(x),g(x))$ in $\int R(f(x),g(x))?$
See Apostol's: Calculus or Courant/Fritz': Introduction to Calculus and Analysis.
Jul
28
asked What's the meaning of the $R(f(x),g(x))$ in $\int R(f(x),g(x))?$
Jul
27
comment What would be interesting maps to use on that Eudoxus reals?
@lulu Yes. But I'm not sure of what $f$ would be useful for this construction of the Eudoxus reals. I'm reading this but it doesn't ring a bell.
Jul
27
comment What would be interesting maps to use on that Eudoxus reals?
@lulu I don't get it. If I take $f(x)=mx+b$, I'd have: $$f(x+y)-f(x)-f(y)=m(x+y)+b-(mx+b)-(my+b)=-b$$ That doesn't seems meaningful.
Jul
27
asked What would be interesting maps to use on that Eudoxus reals?
Jul
22
awarded  Notable Question
Jul
21
accepted Minor mistake computing $\int \frac{1}{x^3+2x^2-3x} \; dx$?
Jul
21
comment Minor mistake computing $\int \frac{1}{x^3+2x^2-3x} \; dx$?
Oh, thanks. When I expanded it in the board, I (wrongly) found $-3c$. Now I expanded it with Mathematica and obtained the right result but didn't pay attention.
Jul
21
asked Minor mistake computing $\int \frac{1}{x^3+2x^2-3x} \; dx$?
Jul
18
asked Does this suggest a unique additive factorization on the rational numbers?
Jul
17
accepted Why $\frac{1}{9}$ becomes $\frac{1}{3}$ in $\frac{1}{3} \int \frac{1}{s^2+1} \, ds$?
Jul
17
comment Why $\frac{1}{9}$ becomes $\frac{1}{3}$ in $\frac{1}{3} \int \frac{1}{s^2+1} \, ds$?
Okay. But is it wrong to use the product rule? Or it's just more practical to use this rule?
Jul
17
awarded  Popular Question