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1h
awarded  Constituent
5h
comment How to solve this kind of problem?
@brick Anything, I guess. I'm not sure if the operations have prority. I just found this randomly on the internet, there were no instructions.
5h
revised How to solve this kind of problem?
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5h
asked How to solve this kind of problem?
22h
comment Continuity of Modified Hom Functor
My eyes switched the letters in my first read. I read Mom Functor.
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asked Could you expand a little on this proof or Floyd-Warshall Algorithm?
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awarded  Famous Question
1d
asked What's the meaning of “reuse space”?
1d
comment Blackboard bold, Bold, Fraktur, and Reserved Variable.
Probably because it's easier to type. **R** is easier than $\mathbb{R}$.
1d
comment Does $\frac{0}{0}$ really equal $1$?
It's actually possible to divide by zero. Take a look at my answer.
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comment Does $\frac{0}{0}$ really equal $1$?
It's actually possible to divide by zero. Take a look at my answer.
1d
revised Does $\frac{0}{0}$ really equal $1$?
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comment Does $\frac{0}{0}$ really equal $1$?
@ConorO'Brien It involves a little bit of abstract algebra, if you're interested (and are able to read mathematics books) take a look at some introduction to abstract algebra. For starters, I guess that Pinter's: A book of algebra or Stillwell's: Elements of Algebra are good calls.
1d
answered Does $\frac{0}{0}$ really equal $1$?
1d
revised is there a discipline of mathematics that studies graphical versions of various operations?
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1d
answered is there a discipline of mathematics that studies graphical versions of various operations?
2d
revised Easy to read books on Graph Theory
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2d
accepted How does $\mathcal{A}\cup \mathcal{B}$ indicates that there is at least one augmenting path on $\mathcal{A}$?
2d
comment How does $\mathcal{A}\cup \mathcal{B}$ indicates that there is at least one augmenting path on $\mathcal{A}$?
Good. I tried to think about it (in the exam) but I didn't imagined the coloring. I tried to think that the matchings $\mathcal{A}$ and $\mathcal{B}$ were disjoint and tried to answer with this. But I noticed that when they happen to be not disjoint, I'd have problems.
2d
asked How does $\mathcal{A}\cup \mathcal{B}$ indicates that there is at least one augmenting path on $\mathcal{A}$?