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 9h accepted The angle between $u$ and $v$ is $30º$, and the vector $w$ of norm $4$ is ortogonal to both $u,v$. Calculate $[u,v,w]$. 9h asked The angle between $u$ and $v$ is $30º$, and the vector $w$ of norm $4$ is ortogonal to both $u,v$. Calculate $[u,v,w]$. 10h revised Suplement books for calculus course? added 124 characters in body May19 comment Why having $ma+np=1$ implies that $m$ is the inverse? Yes. Every multiple of $mp$ of $p$ puts $mp$ in the same class of equivalence, namely $mp=\overline{0}$, then $ma+\overline{0}=1$. I guess I get it now. May19 comment Why having $ma+np=1$ implies that $m$ is the inverse? What do you mean with $[]$? May19 asked Why having $ma+np=1$ implies that $m$ is the inverse? May17 reviewed Approve Clarification on Implicit Derivatives steps May17 comment A silly problem on critical points? @zhw. So those critical points are complex critical points? May17 revised A silly problem on critical points? added 330 characters in body May17 comment A silly problem on critical points? @zhw. Then why Wolfram Alpha says there are critical points? May17 comment A silly problem on critical points? @John Yes. But the problem is that it seems that it's possible to do some magic and use it. Mathematica solves $\sin(x)=2$ as {{x -> ConditionalExpression[\[Pi] - ArcSin[2] + 2 \[Pi] C[1], C[1] \[Element] Integers]}, {x -> ConditionalExpression[ArcSin[2] + 2 \[Pi] C[1], C[1] \[Element] Integers]}}. May17 comment A silly problem on critical points? @John From the page: "$Sin^{-1}(x)$ is the inverse sine function." May17 comment A silly problem on critical points? @John See here. May17 asked A silly problem on critical points? May17 revised Barbeau's Polynomials: Quadratic Polynomials, 1.2.2 edited tags May17 asked Barbeau's Polynomials: Quadratic Polynomials, 1.2.2 May17 accepted Having the roots of a polynomial, is it possible to go back and find a polynomial that have exactly these roots? May17 revised Having the roots of a polynomial, is it possible to go back and find a polynomial that have exactly these roots? edited tags May17 asked Having the roots of a polynomial, is it possible to go back and find a polynomial that have exactly these roots? May14 comment If $n^2=ab$ and $\gcd(a,b)=1$, show that $a,b$ are not necessarily squares. And the author actually gave a similar hint in the beginning of the questions and I completely missed it. I'm so stupid.