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 17m comment $ABCD$ has area $9$. $M$ is in the middle of $AB$ and the edge $BF$ of length $2$ forms an angle of $60º$, Calculate $[CM,CB,BF]$. @RoryDaulton Let's think about $CG$ as $BF$. I assumed that it forms an angle of $60$ on $C$. It's a parallelepiped. 27m asked $ABCD$ has area $9$. $M$ is in the middle of $AB$ and the edge $BF$ of length $2$ forms an angle of $60º$, Calculate $[CM,CB,BF]$. 11h asked What is wrong with my solution to this problem? May25 reviewed Approve Find eigenfunctions of the integral operator with kernel $\sum\limits_{n=1}^\infty \frac{1}{n^2} \sin((n+1)x)\sin(ny)$ May25 reviewed Approve Pareto distribution,fisher information, confidence interval May25 reviewed Approve How to express $[u,v,w]$ as a function of $\phi,\theta$ and the norms of the vectors? May25 accepted Why having $ma+np=1$ implies that $m$ is the inverse? May25 asked How to express $[u,v,w]$ as a function of $\phi,\theta$ and the norms of the vectors? May23 revised The angle between $u$ and $v$ is $30º$, and the vector $w$ of norm $4$ is ortogonal to both $u,v$. Calculate $[u,v,w]$. added 17 characters in body May23 accepted The angle between $u$ and $v$ is $30º$, and the vector $w$ of norm $4$ is ortogonal to both $u,v$. Calculate $[u,v,w]$. May23 asked The angle between $u$ and $v$ is $30º$, and the vector $w$ of norm $4$ is ortogonal to both $u,v$. Calculate $[u,v,w]$. May23 revised Suplement books for calculus course? added 124 characters in body May19 comment Why having $ma+np=1$ implies that $m$ is the inverse? Yes. Every multiple of $mp$ of $p$ puts $mp$ in the same class of equivalence, namely $mp=\overline{0}$, then $ma+\overline{0}=1$. I guess I get it now. May19 comment Why having $ma+np=1$ implies that $m$ is the inverse? What do you mean with $[]$? May19 asked Why having $ma+np=1$ implies that $m$ is the inverse? May17 reviewed Approve Clarification on Implicit Derivatives steps May17 comment A silly problem on critical points? @zhw. So those critical points are complex critical points? May17 revised A silly problem on critical points? added 330 characters in body May17 comment A silly problem on critical points? @zhw. Then why Wolfram Alpha says there are critical points? May17 comment A silly problem on critical points? @John Yes. But the problem is that it seems that it's possible to do some magic and use it. Mathematica solves $\sin(x)=2$ as {{x -> ConditionalExpression[\[Pi] - ArcSin[2] + 2 \[Pi] C[1], C[1] \[Element] Integers]}, {x -> ConditionalExpression[ArcSin[2] + 2 \[Pi] C[1], C[1] \[Element] Integers]}}.