Reputation
Top tag
Next privilege 10,000 Rep.
Access moderator tools
Badges
6 27 86
Impact
~143k people reached

17m
comment $ABCD$ has area $9$. $M$ is in the middle of $AB$ and the edge $BF$ of length $2$ forms an angle of $60º$, Calculate $[CM,CB,BF]$.
@RoryDaulton Let's think about $CG$ as $BF$. I assumed that it forms an angle of $60$ on $C$. It's a parallelepiped.
27m
asked $ABCD$ has area $9$. $M$ is in the middle of $AB$ and the edge $BF$ of length $2$ forms an angle of $60º$, Calculate $[CM,CB,BF]$.
11h
asked What is wrong with my solution to this problem?
May
25
reviewed Approve Find eigenfunctions of the integral operator with kernel $\sum\limits_{n=1}^\infty \frac{1}{n^2} \sin((n+1)x)\sin(ny)$
May
25
reviewed Approve Pareto distribution,fisher information, confidence interval
May
25
reviewed Approve How to express $[u,v,w]$ as a function of $\phi,\theta$ and the norms of the vectors?
May
25
accepted Why having $ma+np=1$ implies that $m$ is the inverse?
May
25
asked How to express $[u,v,w]$ as a function of $\phi,\theta$ and the norms of the vectors?
May
23
revised The angle between $u$ and $v$ is $30º$, and the vector $w$ of norm $4$ is ortogonal to both $u,v$. Calculate $[u,v,w]$.
added 17 characters in body
May
23
accepted The angle between $u$ and $v$ is $30º$, and the vector $w$ of norm $4$ is ortogonal to both $u,v$. Calculate $[u,v,w]$.
May
23
asked The angle between $u$ and $v$ is $30º$, and the vector $w$ of norm $4$ is ortogonal to both $u,v$. Calculate $[u,v,w]$.
May
23
revised Suplement books for calculus course?
added 124 characters in body
May
19
comment Why having $ma+np=1$ implies that $m$ is the inverse?
Yes. Every multiple of $mp$ of $p$ puts $mp$ in the same class of equivalence, namely $mp=\overline{0}$, then $ma+\overline{0}=1$. I guess I get it now.
May
19
comment Why having $ma+np=1$ implies that $m$ is the inverse?
What do you mean with $[]$?
May
19
asked Why having $ma+np=1$ implies that $m$ is the inverse?
May
17
reviewed Approve Clarification on Implicit Derivatives steps
May
17
comment A silly problem on critical points?
@zhw. So those critical points are complex critical points?
May
17
revised A silly problem on critical points?
added 330 characters in body
May
17
comment A silly problem on critical points?
@zhw. Then why Wolfram Alpha says there are critical points?
May
17
comment A silly problem on critical points?
@John Yes. But the problem is that it seems that it's possible to do some magic and use it. Mathematica solves $\sin(x)=2$ as {{x -> ConditionalExpression[\[Pi] - ArcSin[2] + 2 \[Pi] C[1], C[1] \[Element] Integers]}, {x -> ConditionalExpression[ArcSin[2] + 2 \[Pi] C[1], C[1] \[Element] Integers]}}.