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May
7
revised convergence to infinity of$ (2^n + 3^n)^{\frac{1}{n}}$ (as $n \to \infty$)
added 50 characters in body; edited title
May
7
comment Solving $ xy = a + b\cdot\operatorname{lcm}(x,y) + c\cdot\gcd(x,y)$ given $a,b,c$
Nice! I like it.
May
7
comment How many zeroes are in 100!
According to WolframAlpha it would be $29$ zeros in $100!$ (trailing $24$ and $5$ zeroes inside), but if you are looking for a method, as Robert Israel said, there is no known method.
May
6
comment How to find the removeable or infinite discontinuity of any rational function without the factoring of the polynomial?
@Victor you accepted Bill's answer, but yet havn't upvoted.
May
6
comment Find $s$ and $t$ with substitution?
Follow Andre's answer you get $s=9, t=\frac{25}{4}$
May
6
comment Solving an integral
@Jon You have only partially corrected your mistakes. It should be $\sqrt{24}y-1$ and not $\sqrt{24}(y-1)$
May
6
comment $n^2 + 3n +5$ is not divisible by $121$
You got a great answer by Bill, when a number is divisible by $121$ what is it congruent to mod $11^2$?
May
6
comment The maximum number of nodes in a binary tree of depth $k$ is $2^{k}-1$, $k \geq1$.
@rajansthapit what is the name of tile/author of the book? Gadi has the correct answer.
May
6
answered Derivative of $e^{-x}$
May
6
comment The Importance Of Good Teachers and Guidance In the Academics
Today at least there are tons of resources as an alternative, assuming you are self-motivated. If a teacher is not good, it really brings down the confidence of a student (Personally from what I noticed in my Son's case).
May
6
comment If $x$ and $y$ are rational numbers and $x^5+y^5=2x^2y^2,$ then $1-xy$ is a perfect square.
My +1 and Thanks.
May
6
comment If $b^2$ is the largest square divisor of $n$ and $a^2 \mid n$, then $a \mid b$.
@BillDubuque Recommend the long line to be split as $$ \begin{align*} a^2 | b^2c \Rightarrow a^2 | (bc)^2 &\Rightarrow a^2 | a^2c, abc, b^2c \\ &\Rightarrow a^2 | (a,b)^2c \Rightarrow (a/(a,b))^2 | c \end{align*} $$ My +1 for this answer.
May
6
comment Result of the product $0.9 \times 0.99 \times 0.999 \times …$
@PaulManta this converges to $0.89$, but you have to think how to show that.
May
6
comment Result of the product $0.9 \times 0.99 \times 0.999 \times …$
@PaulManta I changed the \cdots to \times because it was confusing with the numbers themselves with decimal values.
May
6
revised Result of the product $0.9 \times 0.99 \times 0.999 \times …$
edited title
May
6
comment Result of the product $0.9 \times 0.99 \times 0.999 \times …$
How about $(1-\frac{1}{10})(1-\frac{1}{100})...= \prod_{i=0}^{\infty}(1-\frac{1}{10^i}) $
May
6
awarded  Necromancer
May
5
awarded  Nice Answer
May
5
comment Find the sum of $\sum 1/(k^2 - a^2)$ when $0<a<1$
@N3buchadnezzar your expected answer has an error. Checked against Wolfram Alpha's snipurl.com/23dq2hp and instead of plus sign, it shows minus sign. Follow J.M's hint, your might approach the answer.
May
5
comment If $x$ and $y$ are rational numbers and $x^5+y^5=2x^2y^2,$ then $1-xy$ is a perfect square.
@dato, the original question was prove $1-xy$ is a perfect square, so there is a proof required, not solutions to $x,y$.