Kirthi Raman
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 May6 comment Find $s$ and $t$ with substitution? Follow Andre's answer you get $s=9, t=\frac{25}{4}$ May6 comment Solving an integral @Jon You have only partially corrected your mistakes. It should be $\sqrt{24}y-1$ and not $\sqrt{24}(y-1)$ May6 comment $n^2 + 3n +5$ is not divisible by $121$ You got a great answer by Bill, when a number is divisible by $121$ what is it congruent to mod $11^2$? May6 comment The maximum number of nodes in a binary tree of depth $k$ is $2^{k}-1$, $k \geq1$. @rajansthapit what is the name of tile/author of the book? Gadi has the correct answer. May6 answered Derivative of $e^{-x}$ May6 comment The Importance Of Good Teachers and Guidance In the Academics Today at least there are tons of resources as an alternative, assuming you are self-motivated. If a teacher is not good, it really brings down the confidence of a student (Personally from what I noticed in my Son's case). May6 comment If $x$ and $y$ are rational numbers and $x^5+y^5=2x^2y^2,$ then $1-xy$ is a perfect square. My +1 and Thanks. May6 comment If $b^2$ is the largest square divisor of $n$ and $a^2 \mid n$, then $a \mid b$. @BillDubuque Recommend the long line to be split as \begin{align*} a^2 | b^2c \Rightarrow a^2 | (bc)^2 &\Rightarrow a^2 | a^2c, abc, b^2c \\ &\Rightarrow a^2 | (a,b)^2c \Rightarrow (a/(a,b))^2 | c \end{align*} My +1 for this answer. May6 comment Result of the product $0.9 \times 0.99 \times 0.999 \times …$ @PaulManta this converges to $0.89$, but you have to think how to show that. May6 comment Result of the product $0.9 \times 0.99 \times 0.999 \times …$ @PaulManta I changed the \cdots to \times because it was confusing with the numbers themselves with decimal values. May6 revised Result of the product $0.9 \times 0.99 \times 0.999 \times …$ edited title May6 comment Result of the product $0.9 \times 0.99 \times 0.999 \times …$ How about $(1-\frac{1}{10})(1-\frac{1}{100})...= \prod_{i=0}^{\infty}(1-\frac{1}{10^i})$ May6 awarded Necromancer May5 awarded Nice Answer May5 comment Find the sum of $\sum 1/(k^2 - a^2)$ when \$0