network profile
| bio | website | |
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| location | ||
| age | ||
| visits | member for | 1 year, 3 months |
| seen | 14 hours ago | |
| stats | profile views | 138 |
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Jun 11 |
comment |
How can I solve this differential equation? It is so called an Euler Equation. For details you may check math.dartmouth.edu/archive/m23s06/public_html/handouts/… |
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Jun 5 |
suggested | suggested edit on How to find the value of $k$ for the density function defined by $f(x)=kx^2$? |
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May 31 |
comment |
Type of singularities of $\frac{z}{e^z-1}$ Then $z=0$ is removable. |
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May 30 |
revised |
One Dimensional Wave Equation (Fritz John page45) added a tag and refined the body |
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May 30 |
suggested | suggested edit on One Dimensional Wave Equation (Fritz John page45) |
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May 27 |
revised |
Prove $a^n \rightarrow 0$ as $n \rightarrow \infty$ for $\left|a\right| < 1$ without use of log properties corrected notation |
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May 27 |
suggested | suggested edit on Prove $a^n \rightarrow 0$ as $n \rightarrow \infty$ for $\left|a\right| < 1$ without use of log properties |
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May 26 |
revised |
Prove $\sin \left(1/n\right)$ tends to $0$ as $n$ tends to infinity. added 7 characters in body |
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May 26 |
answered | Prove $\sin \left(1/n\right)$ tends to $0$ as $n$ tends to infinity. |
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May 26 |
answered | Calculate big-$\Theta$ for $T(x) = \log(x2x!)$ |
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May 26 |
comment |
Calculate big-$\Theta$ for $T(x) = \log(x2x!)$ Do you mean $\log(x (2x)!)$? |
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May 22 |
comment |
Solve $ z= \frac{2a^2}{-4+z} + \frac{2a^4}{(-4+z)^2(-16+z)} + \cdots $. Glad for your understanding. I agree that with this hypothesized equation, it is not possible to evaluate $z$ further in terms of $a$. There is a heavy machinary to give a formula for $z$ so I didn't mention it in the question. On the other hand, I understand that Taylor series is the most convenient way to handle the problem with this piece of information. Thanks for your help. |
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May 21 |
comment |
Solve $ z= \frac{2a^2}{-4+z} + \frac{2a^4}{(-4+z)^2(-16+z)} + \cdots $. @GregMartin I am very sorry about my comments. After downvotes and negative comments (which I perceived as offensive), the above absurdity happened. I apologize for this nonsense. |
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May 21 |
comment |
Solve $ z= \frac{2a^2}{-4+z} + \frac{2a^4}{(-4+z)^2(-16+z)} + \cdots $. I am just looking for a different method and it is enough to have in mind that we can continue the expansion, that's all. Besides, there are solutions up to this extend, just check out the comment of @AntonioVargas. As far as I understand, you are fighting for reputation and succeed in some "sense". Congrats! Further, you are not able to suggest any other method like 'Continued Fractions' for the question, right? |
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May 21 |
comment |
Solve $ z= \frac{2a^2}{-4+z} + \frac{2a^4}{(-4+z)^2(-16+z)} + \cdots $. @GregMartin Your observation is useless in practice. |
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May 21 |
comment |
Solve $ z= \frac{2a^2}{-4+z} + \frac{2a^4}{(-4+z)^2(-16+z)} + \cdots $. @AntonioVargas I checked my computations and you're right! Thanks! |
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May 20 |
revised |
Riemann integral show $f(x)=g(x)$ for at least 1 $x$ in [a,b] corrected the typing |
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May 20 |
suggested | suggested edit on Riemann integral show $f(x)=g(x)$ for at least 1 $x$ in [a,b] |
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May 20 |
comment |
Solve $ z= \frac{2a^2}{-4+z} + \frac{2a^4}{(-4+z)^2(-16+z)} + \cdots $. @ThomasAndrews actually there is, but really hard to formulate here. |
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May 20 |
asked | Solve $ z= \frac{2a^2}{-4+z} + \frac{2a^4}{(-4+z)^2(-16+z)} + \cdots $. |
