7,976 reputation
1642
bio website people.bath.ac.uk/mdp33
location Bath, United Kingdom
age 24
visits member for 2 years, 5 months
seen 14 mins ago

Postgraduate student at the University of Bath, UK, studying geometry and representation theory. Currently thinking about cluster algebras and related objects.


Sep
17
answered Find the tangent to $f(x)$
Sep
17
reviewed No Action Needed automorphism of a rooted tree
Sep
16
reviewed Leave Open How to compute $\lim_{n\rightarrow\infty}\frac1n\left\{(2n+1)(2n+2)\cdots(2n+n)\right\}^{1/n}$
Sep
16
reviewed No Action Needed Counting number of solutions for $x = (a-1)(b-2)(c-3)(d-4)(e-5)$
Sep
16
reviewed Approve suggested edit on Maximum of two positive operators
Sep
16
reviewed Looks OK What is the sum of this series?
Sep
14
reviewed No Action Needed Creating feature vectors with a high degree of entropy from the actual training data for neural network?
Sep
14
reviewed Reviewed Prove that the field F is a vector space over itself.
Sep
14
reviewed Reopen Product of divisors of two coprimes
Sep
14
reviewed Close $[E:F]$ can be divided by $|Gal(E/F)| $?
Sep
13
awarded  Good Answer
Sep
10
comment Proof for cyclic permutation
Write $a=(a_1,a_2,\dotsc,a_r)$, let $x$ be an element of $\{1,\dotsc,n\}$, and see what happens when you apply $a$ to $x$ $r$ times.
Sep
10
reviewed Approve suggested edit on Asymptotic bounds. What software to use?
Sep
10
comment Proving that 4 specified sets are not algebraic
For 3 and 4, assume $f$ is a polynomial vanishing on your specified set. Then by restricting to each line through the origin (i.e., set $y=\lambda x$ for some $\lambda$, or $x=0$), you can get a bunch of polynomials of one variable, each of which has infinitely many roots, so must be $0$. Thus you can show that $f$ vanishes everywhere. Possibly a similar method can be adapted to the others.
Sep
10
reviewed Close Twice as much vs Two times as much vs Double
Sep
10
reviewed Leave Open A map that is surjective but not injective between infinite dimensional vector spaces
Sep
10
reviewed Leave Open A form problem between $S^3$ and $S^2$.
Sep
10
reviewed Close A property of rings
Sep
10
reviewed Close A ring with few invertible elements
Sep
10
answered Show that $\operatorname{Hom}_R(M, -)$ is a functor from the category of $R$-modules to the category of abelian groups.