Matt Pressland

5,359 reputation

1135

bio	website	people.bath.ac.uk/mdp33
	location	Bath, United Kingdom
	age	23
visits	member for	1 year, 3 months
	seen	yesterday
stats	profile views	430

Postgraduate student at the University of Bath, UK, studying geometry and representation theory. Currently thinking about cluster algebras and related objects.

	5,359 reputation	bio	website	people.bath.ac.uk/mdp33	visits	member for	1 year, 3 months
1135 badges		location	Bath, United Kingdom		seen	yesterday

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1d	comment	Logarithmic equation. Need to know if i am teaching right But you don't know what $x$ and $y$ are - the point is to write everything in terms of $\log{x}$ and $\log{y}$.
1d	answered	Solve a simple equation with log in it
1d	awarded	Enlightened
2d	awarded	Nice Answer
2d	comment	Defining a subset In case it proves useful, here: www03.edu.fi/oppimateriaalit/matematiikansanakirja/ohjelma/… is a dictionary that translates mathematical terms between English, Swedish, Finnish and Russian.
2d	comment	Are these 2 graphs isomorphic? @KevinDuke There is no edge between vertices 5 and 7. I agree with Gerry that they appear to be isomorphic, and that the easiest way to show this is to write down an isomorphism.
May 15	comment	Subvariety of an Algebraic Group. If we're allowed to know the non-geometric information of which point is the identity, then a potentially interesting question is whether every subvariety of $G$ can be mapped to a subgroup by multiplying by a group element. Thinking about this question in reverse, it becomes "is every subvariety of $G$ a coset of some subgroup $H$?".
May 15	comment	Subvariety of an Algebraic Group. I doubt a geometric characterization is possible, precisely because $G$ has automorphisms (say, multiplication by a non-identity element) that don't preserve the identity. More basically, you can't tell geometrically which point is the trivial subgroup.
May 15	comment	What's the intuition behind this equality involving combinatorics? This answer is basically a wordier version of André's, who was first, but I decided to post it anyway for the first paragraph.
May 15	answered	What's the intuition behind this equality involving combinatorics?
May 14	comment	Partial Solution to the Twin Primes Conjecture — What does it imply? One important question that people often forget to ask is whether the methods used to prove the result have implications in other areas (e.g. Fermat's Last Theorem). I don't know whether that is the case here, but knowing a way to solve a difficult problem is sometimes more useful than knowing the solution.
May 14	comment	What is $\lim_{n \rightarrow \infty}\sum\limits_{k = 1}^n\frac{k}{n^2}$? You seem to be trying to use the sum rule for sequences - this only works when the number of terms in the sum is constant, but in this case it grows with $n$. The first step in this answer is the result $\sum_{i=1}^ni=\frac{1}{2}n(n+1)$.
May 14	revised	What is $\lim_{n \rightarrow \infty}\sum\limits_{k = 1}^n\frac{k}{n^2}$? edited title
May 14	reviewed	Approve suggested edit on What is $\lim_{n \rightarrow \infty}\sum\limits_{k = 1}^n\frac{k}{n^2}$?
May 14	comment	Why do the French count so strangely? @HenningMakholm Fair enough! Apologies for my cheap shot based on trying to speak Swedish in Denmark!
May 14	comment	Why do the French count so strangely? @HenningMakholm Even if I don't pronounce any of the consonants? ;-)
May 14	comment	Why do the French count so strangely? @Hagen If I was to just say femtifem, people would know what I meant, right?! Femoghalftres looks too much like six and a half to me!
May 14	comment	Why do the French count so strangely? Another suggestion I've heard is that some cultures count both above and below the larger knuckle on each finger to end up with base 20. Others also use gaps between the fingers in conjunction with various parts of each finger to get some strange bases.
May 13	awarded	Nice Answer
May 13	comment	Do we really need polynomials (In contrast to polynomial functions)? @temo Apologies, I'm not sure now what I read there instead of what you wrote. The other answers expand on the reasons for this a lot more (as I'd hoped would happen). Maybe this answer should even have been a comment, I thought it was borderline when I wrote it.