Reputation
2,002
Top tag
Next privilege 2,500 Rep.
Create tag synonyms
Badges
15 38
Newest
 Talkative
Impact
~99k people reached

Apr
30
asked Natural Logarithm and Integral Properties
Apr
30
accepted Determining the Length of a Curve Using Partitions
Apr
27
accepted Curve In a Closed Interval with an Infinite Length
Apr
27
asked Curve In a Closed Interval with an Infinite Length
Apr
27
comment Determining the Length of a Curve Using Partitions
You just shed a ton of light on this problem for me! However, I have a few questions: for the first question, how could the sums of $Q$ be smaller than those of $P$, when we have already assumed that $Q\supseteq P$? And for the second question, would taking the sequence $P_1=[a,b]$, $P_2=[a,\frac{a+b}{2},b]$, $P_3=[a,\frac{3a+b}{4},\frac{a+b}{2},\frac{a+3b}{4},b]$, $\dots$ be a good start?
Apr
27
asked Determining the Length of a Curve Using Partitions
Apr
26
accepted Showing that $\cos\left(\frac{\pi}{5}\right)=\frac{1}{2}\phi?$
Apr
25
asked Showing that $\cos\left(\frac{\pi}{5}\right)=\frac{1}{2}\phi?$
Apr
25
comment If $m$ and $n$ are positive integers, then $(F_m,F_n)=F_{(m,n)}$.
I understand now. :) Thanks, guys!
Apr
25
comment If $m$ and $n$ are positive integers, then $(F_m,F_n)=F_{(m,n)}$.
There's a step where he states that $(f_{n-m},f_m)=f_{(n-m,m)}$. Is that something that's well-known?
Apr
25
revised If $m$ and $n$ are positive integers, then $(F_m,F_n)=F_{(m,n)}$.
edited body
Apr
25
asked If $m$ and $n$ are positive integers, then $(F_m,F_n)=F_{(m,n)}$.
Apr
25
comment Showing that $f_{2n+1}=f_{n+1}^2+f_n^2$.
I like this approach a lot. Thanks!
Apr
25
accepted Showing that $f_{2n+1}=f_{n+1}^2+f_n^2$.
Apr
25
comment Showing that $f_{2n+1}=f_{n+1}^2+f_n^2$.
How did you obtain that? Did you know it beforehand?
Apr
25
revised Showing that $f_{2n+1}=f_{n+1}^2+f_n^2$.
edited body
Apr
25
asked Showing that $f_{2n+1}=f_{n+1}^2+f_n^2$.
Apr
25
accepted If $f$ is increasing and continuous on $[a,b]$, then it is integrable there.
Apr
24
asked If $f$ is increasing and continuous on $[a,b]$, then it is integrable there.
Apr
23
accepted Permutation Group Notation