276 reputation
112
bio website
location
age 22
visits member for 2 years, 6 months
seen Apr 27 at 20:24

I'm a Computer Science & Mathematics double major who has an avid interest in Android and Google. I also know a bit about C (Objective-C as well), but my main focus is Android, and as a result, Java.


1d
awarded  Popular Question
Jul
2
awarded  Curious
May
16
awarded  Popular Question
Feb
26
awarded  Popular Question
Nov
26
awarded  Popular Question
Sep
26
awarded  Popular Question
Sep
17
accepted Let $C$ be a set of sets defined as follows,
Sep
17
comment Let $C$ be a set of sets defined as follows,
Oh yeah, I'm really smart. So the elements of $C$ either have cardinality of 1 due to (1), 2 due to (2), or powers of 2 due to (3).
Sep
17
comment Let $C$ be a set of sets defined as follows,
Ok good, because now it makes sense. So clearly there are no infinite sets in $C$ because for $S, T\in C$ $|\{S, T\}| = |S|+|T|$ and $|S\times T|=|S|*|T|$. But it's uncountable because there are infinitely many ways to combine elements of $C$ using either (2) or (3), right? I can't think of a way in which $C$ could be countable.
Sep
17
comment Let $C$ be a set of sets defined as follows,
Oh okay that makes sense. But do we know anything other than constructions based on the empty set?
Sep
17
comment Let $C$ be a set of sets defined as follows,
Thank you, that was part a) actually. I figured that out similarly to how you've done it. What I'm struggling with is understanding how ordered pairs can come into play. If we let $S=\{(a,b),(c,d)\}$ for example, we can have $\{S,\emptyset\}$, but how do I know that's in $C$?
Sep
17
asked Let $C$ be a set of sets defined as follows,
Feb
15
awarded  Yearling
Nov
1
comment Aristotle's Axiom in Hyperbolic Geometry
@Berci Yes, that is the Angle Unboundedness Axiom in Euclidean/Neutral geometry, but I need to figure out a way to prove that statement holds in Hyperbolic geometry.
Nov
1
asked Aristotle's Axiom in Hyperbolic Geometry
Oct
22
accepted Proving a function $f$ is continuous at a point $a$
Oct
22
comment Proving a function $f$ is continuous at a point $a$
Okay, got it. Thank you very much!!
Oct
22
comment Proving a function $f$ is continuous at a point $a$
Okay, so because $f$ is continuous, there exists a specific $\delta_{\frac{\epsilon}{2}}$ such that, if $x\in(a-\delta_{\frac{\epsilon}{2}},a+\delta_{\frac{\epsilon}{2}})$ then $|f(x)-f(a)|<\frac{\epsilon}{2}$, just because of the definition of continuity?
Oct
22
comment Proving a function $f$ is continuous at a point $a$
Then we'd have $|f(x)-f(y)|<\epsilon$! Brilliant, I'd never think to use the Triangle Inequality here, but what value of $\delta_\epsilon$ can we pick to make this work? I'm a little shaky on how the values of $\delta$ can affect the value of $\epsilon$.
Oct
22
revised Proving a function $f$ is continuous at a point $a$
Figured parts of it out, but still need help with another part.