Yong Pan
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 Aug 12 awarded Yearling Dec 9 asked Is the $n$-sphere $x_1^2+\cdots+x_n^2-1=0$ a rational variety in $\mathbb{A}^n$? Dec 8 accepted Why does $\operatorname{tr}(A^k)=\operatorname{tr}(B^k)$ imply $\operatorname{Spec}(A)=\operatorname{Spec}(B)$? Dec 8 comment Why is the extension $k(x,\sqrt{1-x^2})/k$ purely transcendental? Thanks so much! I really appreciate this answer. Dec 8 accepted Why is the extension $k(x,\sqrt{1-x^2})/k$ purely transcendental? Dec 7 asked Why is the extension $k(x,\sqrt{1-x^2})/k$ purely transcendental? Oct 10 asked Can a smooth function $f\colon\partial D^n\to\partial D^n$ be extended to a smooth function $\hat{f}\colon D^n\to D^n$? Sep 24 awarded Autobiographer Jul 2 awarded Curious Nov 29 awarded Disciplined Aug 15 comment Why does $\operatorname{tr}(A^k)=\operatorname{tr}(B^k)$ imply $\operatorname{Spec}(A)=\operatorname{Spec}(B)$? @Babgen Thanks, that sounds interesting, but I don't follow. The $k$th row of the Vandermonde matrix would be the eigenvalues of the $k$th power. But how does taht relate to the specific eigenvalues themselves? Aug 15 asked Why does $\operatorname{tr}(A^k)=\operatorname{tr}(B^k)$ imply $\operatorname{Spec}(A)=\operatorname{Spec}(B)$? Jun 25 awarded Critic Jun 25 comment Is a linear functional on $\mathbb{R}^n$ positive if and only if its Riesz vector is positive? How do you figure that? It doesn't seem like $r_f$ is even an element of $S$. Jun 25 revised Is a linear functional on $\mathbb{R}^n$ positive if and only if its Riesz vector is positive? edited title Jun 25 asked Is a linear functional on $\mathbb{R}^n$ positive if and only if its Riesz vector is positive? Feb 15 awarded Yearling Feb 7 accepted Product of monic irreducibles with degree dividing $n$ has no repeated roots? Jan 25 asked Product of monic irreducibles with degree dividing $n$ has no repeated roots? Sep 28 accepted Is $[0,1)\times[0,1]$ a linear continuum?