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Aug
29
accepted Joint Convexity Proof
Aug
27
accepted Extension of metric definition to two sets
Aug
23
accepted Biconjugate of a nonconvex function
Aug
20
asked Biconjugate of a nonconvex function
Aug
19
comment Joint Convexity Proof
Thanks. Yes, I was missing some assumptions. Hope it is right now.
Aug
19
revised Joint Convexity Proof
Mistakes fixed.
Aug
19
asked Joint Convexity Proof
Aug
19
comment Extension of metric definition to two sets
Thanks! That is useful @celtschk!
Aug
18
comment Extension of metric definition to two sets
Thanks! Yes I see these problems, but I still know a heterogeneous metric is learned, e.g. in machine learning. My question is mainly about how can we mathematically deal with the definition of metric. What CC0607 suggests is close to the idea of heterogeneous metric learning, however, I am not sure yet if the metric can be defined on $X \times Y$, in some way, or on $Z \times Z$ only.
Aug
18
comment Extension of metric definition to two sets
That is awesome @Ronnie Brown. Thanks so much for sharing!
Aug
18
comment Extension of metric definition to two sets
@CC0607 Thanks! Then the metric would be on $Z$, i.e. $Z\times Z \to \mathbb{R}$, right? Otherwise, from $X\times Y \to \mathbb{R}$, it would not be well-defined? Or I am missing something?
Aug
18
comment Extension of metric definition to two sets
My intuitive response is that the distance between "the concept of metric" and a "monkey", how ever it is defined, is larger than the distance between "the concept of monkey" and a "monkey".
Aug
18
asked Extension of metric definition to two sets
Aug
2
awarded  Notable Question
May
21
awarded  Popular Question
Apr
23
accepted Augmented Lagrangian Method for Inequality Constraints
Apr
21
asked What is an inner-outer iteration?
Apr
21
revised Rank of product of a matrix and its transpose
added 234 characters in body
Apr
21
comment Augmented Lagrangian Method for Inequality Constraints
@ Michael, Good point! fixed! Thank you.
Apr
21
comment Augmented Lagrangian Method for Inequality Constraints
@ littleO I want to understand how I can use Augmented Lagrangian, when I have inequality constraints, using this method. The equivalent question is how does LCL work exactly.