396 reputation
28
bio website
location
age
visits member for 1 year, 3 months
seen May 1 at 19:37
stats profile views 69

Feb
9
awarded  Yearling
Feb
5
asked Terminology: how to call the compact version of an affine space?
Jan
29
accepted Essential selfadjointness preserved under unitarily transfomration?
Jan
20
revised Essential selfadjointness preserved under unitarily transfomration?
improved notation
Jan
20
asked Essential selfadjointness preserved under unitarily transfomration?
Nov
13
awarded  Enthusiast
Oct
30
answered Unbounded operator on $\mathcal{C}([0,1])$ with the norm $L_1$
Oct
27
accepted Bounding $h^{-1}|e^{hy}-1|$
Oct
27
comment Bounding $h^{-1}|e^{hy}-1|$
In the previous comment I mean $h$ small of course ($h=\frac{1}{100}$)...
Oct
27
comment Bounding $h^{-1}|e^{hy}-1|$
@Mercy. $f_h(x)\leq |x|$ is not true. Take $y=\frac{1}{h^2}$ and $h$ large (say h=100). Note that also $f_h(x)\leq |x|^N$ is not true for any fixed $N\in\mathbb N$.
Oct
27
asked Bounding $h^{-1}|e^{hy}-1|$
Oct
24
comment Smooth function on $\mathbb R$ whose small increments are not controlled by the first derivative at infinity
Tanks, this is what I was looking for!
Oct
24
comment Smooth function on $\mathbb R$ whose small increments are not controlled by the first derivative at infinity
I accept the other answer because it is bit simpler, but this is interesting anyway, thanks!
Oct
24
accepted Smooth function on $\mathbb R$ whose small increments are not controlled by the first derivative at infinity
Oct
24
comment Inner product and infinite sum
The series converges in the Hilbert norm, right? Then I agree with Tomás, the question does not depend on wether $H$ is a function space or not. Your argument seems correct to me (you use continuity of the scalar product) and the assumption that $(a_n)$ is square summable is redundant I think.
Oct
22
revised Smooth function on $\mathbb R$ whose small increments are not controlled by the first derivative at infinity
added my intuition
Oct
22
revised Smooth function on $\mathbb R$ whose small increments are not controlled by the first derivative at infinity
added absolute value for $h$
Oct
22
comment Smooth function on $\mathbb R$ whose small increments are not controlled by the first derivative at infinity
@LukasGeyer and Robert Israel. Thanks for your comments, I edited, hope it is clear now (yes the "sufficiently small" should be uniform in $x$). With oscillating I meant not the function itself, but higher derivatives. Anyway I cancelled the comment on the oscillations, maybe it is only confusing.
Oct
22
revised Smooth function on $\mathbb R$ whose small increments are not controlled by the first derivative at infinity
deleted 52 characters in body
Oct
22
comment Smooth function on $\mathbb R$ whose small increments are not controlled by the first derivative at infinity
ops, I forgot to write that I want also the first derivative bounded away from zero..see edit. sorry.