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bio website joezeng.com
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age 21
visits member for 2 years, 9 months
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2h
comment I can't grasp how these events are independent?
Reread my answer, and then answer the question: "Given that B has happened, is the probability of $A$ happening any different than the probability of $A$ happening in general?" If $B$ has happened, then we're no longer looking at the entire set $S$ to figure out whether $A$ has happened, only the 5 elements in $B$. So the probability becomes 2 out of 5, rather than 2 out of 10. You can't just compare raw set sizes; probability is always a ratio.
3h
comment I can't grasp how these events are independent?
Probably because conditional probability isn't part of your intuition yet. It takes a bit of time to learn.
3h
comment I can't grasp how these events are independent?
Basically, you were comparing the wrong things there $-$ you should be comparing $P(B|A)$ and $P(B)$, not $P(AB)$ and $P(B)$.
3h
answered I can't grasp how these events are independent?
Nov
21
comment $Ax+By+Cz=D \text { has a solution iff } \gcd(\gcd(A,B),C)\mid D$
This is the Euclidean Algorithm, I think.
Nov
18
revised Volume of a split log
LaTeX
Nov
18
answered Volume of a split log
Nov
11
awarded  Excavator
Nov
11
revised How can I formulate the two guards puzzle to disallow references to the other guard?
added 93 characters in body
Nov
4
comment Find the number of ways in which 10 different books can be shared between a boy and a girl if each is to receive an even number of books.
252 is the correct answer to each child receiving exactly five books.
Sep
30
awarded  Explainer
Jul
25
revised Examples of sub-exponential functions that aren't exponential functions when chained by a polynomial
Guess I'll correct the asymptotic notation.
Jul
20
awarded  Popular Question
Jul
16
awarded  Nice Question
Jul
16
comment Is there a function such that $f(f(n)) = 2^n$?
What is that $W$?
Jul
16
comment Examples of sub-exponential functions that aren't exponential functions when chained by a polynomial
Yeah, I meant $\Omega(2^n)$. I'm too used to using big $O$ notation as a misnomer for that.
Jul
16
comment Is there a function such that $f(f(n)) = 2^n$?
Unfortunately, I can't read German :(
Jul
16
comment Is there a function such that $f(f(n)) = 2^n$?
That is indeed a possibility.
Jul
16
comment Is there a function such that $f(f(n)) = 2^n$?
That question didn't appear at all in the list of suggested questions while I was writing this question. I wonder why.
Jul
16
revised Is there a function such that $f(f(n)) = 2^n$?
added 95 characters in body