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 Tumbleweed
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comment Simple module over a basic algebra is one-dimensional
I just had the same question about this exact same document, very helpful answer.
Aug
25
asked Nakayama automorphism $\sigma$ of Hecke Algebra $^0H^f_n$ is not inner for $n\geq 3$?
Aug
25
awarded  Tumbleweed
Aug
20
accepted Functor $M\otimes_B -$ is left and right adjoint to $\operatorname{Hom}_A(M,-)$ when there is a symmetrizing form for $A$?
Aug
20
comment Functor $M\otimes_B -$ is left and right adjoint to $\operatorname{Hom}_A(M,-)$ when there is a symmetrizing form for $A$?
Thanks Jeremy. If $A$ is a symmetric $R$-algebra, is $A\cong\operatorname{Hom}_R(A,R)$ definition? The only notion of symmetric algebra I know about is the quotient of the tensor algebra for a vector space $V$, $\operatorname{Sym}(V)=T(V)/(v\otimes w-w\otimes v)$, but I'm not sure if that's what they're talking about.
Aug
19
asked Functor $M\otimes_B -$ is left and right adjoint to $\operatorname{Hom}_A(M,-)$ when there is a symmetrizing form for $A$?
Aug
17
asked If $M$ is an $A$-module via $\varphi\colon A\to\operatorname{End}(M)$, $\mathrm{coker}(\varphi)\otimes M$ is projective?
Aug
6
comment Why does $\sum_{\sigma\in S_n}q^{\ell(\sigma)}=\frac{(1-q)(1-q^2)\cdots(1-q^n)}{(1-q)^n}$?
Thanks everybody.
Aug
6
accepted Why does $\sum_{\sigma\in S_n}q^{\ell(\sigma)}=\frac{(1-q)(1-q^2)\cdots(1-q^n)}{(1-q)^n}$?
Aug
6
awarded  Disciplined
Aug
6
revised Why does $\sum_{\sigma\in S_n}q^{\ell(\sigma)}=\frac{(1-q)(1-q^2)\cdots(1-q^n)}{(1-q)^n}$?
added 15 characters in body
Aug
6
asked Why does $\sum_{\sigma\in S_n}q^{\ell(\sigma)}=\frac{(1-q)(1-q^2)\cdots(1-q^n)}{(1-q)^n}$?
Aug
5
comment If $g=(n-j,\dots,n)$ and $\sigma\in S_{n-1}$, why are the inversions of $g\sigma$ the union of the inversions of $\sigma$ and $g$?
@darij That worked out, many thanks.
Aug
5
revised If $g=(n-j,\dots,n)$ and $\sigma\in S_{n-1}$, why are the inversions of $g\sigma$ the union of the inversions of $\sigma$ and $g$?
added 168 characters in body
Aug
5
asked If $g=(n-j,\dots,n)$ and $\sigma\in S_{n-1}$, why are the inversions of $g\sigma$ the union of the inversions of $\sigma$ and $g$?
Apr
22
accepted Is taking the product of quasi-projective varieties associative?
Jan
6
asked Is taking the product of quasi-projective varieties associative?
Jan
6
comment Are the quasi-affine subsets of $\mathbb{A}^1_F$ necessarily open or closed?
Ah, I see, the closed sets are the finite ones, or all of $\mathbb{A}^1$. Thanks KReiser, I like the use of a full solution under spoiler text.
Jan
6
accepted Are the quasi-affine subsets of $\mathbb{A}^1_F$ necessarily open or closed?
Nov
12
asked Are the quasi-affine subsets of $\mathbb{A}^1_F$ necessarily open or closed?