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Mar
7
revised Proving a matrix is positive definite using Cholesky decomposition
Edited for clarity and latexed...
Mar
7
suggested approved edit on Proving a matrix is positive definite using Cholesky decomposition
Mar
7
answered Proving a matrix is positive definite using Cholesky decomposition
Mar
6
comment Guessing the probability by results of just 1 experiment
If you can carry out just one toss, the only definitive conclusion you can make is $X\ne 0$.
Mar
6
revised How to get transition rates in a $M/M/\infty$ queue
made some changes for clarity.
Mar
6
revised How to get transition rates in a $M/M/\infty$ queue
added 7 characters in body
Mar
6
suggested approved edit on How to get transition rates in a $M/M/\infty$ queue
Mar
5
answered X has pdf $f(x) = \frac{x^{2}}{18}$ for -3<x<3, what is the pdf of $X^{2}$
Mar
5
answered what is the median of the CDF with the form $F(x) = 1 - e^{-(x/3)^2}$, for $x \gt 0$
Mar
5
comment How to get transition rates in a $M/M/\infty$ queue
@Rosie: Sorry, pls. replace packets with people :) I study this from a communication networks perspective...
Mar
5
comment How to get transition rates in a $M/M/\infty$ queue
@Rosie: It is not about the number of servers, but the number of packets, which is $n$. To understand about the minimum, say you are in a state with $n$ packets and ask "When will I change from this state?" The answer for this is the minimum of the interarrival time and the $n$ service times for each of the packets.
Mar
5
answered How to get transition rates in a $M/M/\infty$ queue
Mar
5
revised Minumum of a function
added 212 characters in body
Mar
5
comment Probablity that the drawn number is greater than the previously drawn
Which means $A_k=(x_k=1)\mid H_{k-1}$, or $A_k$ is the event of the $k^{th}$ number being the highest "given" you have observed some $k-1$ numbers before.
Mar
5
comment Probablity that the drawn number is greater than the previously drawn
I'll try to explain. $A_k$ is the event that the $k^{th}$ number is the highest of all $k$ numbers you have observed so far. Unconditionally the probability that the $k^{th}$ number is the highest is $P(x_k=1)=1/k$. But we have observed some $k-1$ numbers so far and we need $P(x_k=1\mid H_{k-1})$.
Mar
5
answered Minumum of a function
Mar
5
comment Probablity that the drawn number is greater than the previously drawn
Because when you say "than all previously drawn", what you essentially mean is "given all numbers I have observed" or in other words, "given the history so far" - this is captured by $H_{k-1}$.
Mar
5
revised Probablity that the drawn number is greater than the previously drawn
adding a necessary detail to the question.
Mar
5
comment How to recover a shuffled matrix
Can't see anything there to "show".
Mar
5
suggested approved edit on Probablity that the drawn number is greater than the previously drawn