90 reputation
7
bio website
location
age
visits member for 2 years, 2 months
seen Apr 4 at 5:40

Mar
11
accepted Strong Morita equivalence - Question about proof in Beer's “On Morita equivalence of nuclear $C^*$-algebras”
Mar
6
comment Strong Morita equivalence - Question about proof in Beer's “On Morita equivalence of nuclear $C^*$-algebras”
Thank you, I suppose I can find that (and more on the subject) in an introductory level book on Hilbert modules? Thanks for your answer.
Mar
1
asked Strong Morita equivalence - Question about proof in Beer's “On Morita equivalence of nuclear $C^*$-algebras”
Mar
26
awarded  Scholar
Mar
26
accepted Resolutions of bimodules as $R^e$-modules.
Mar
24
awarded  Commentator
Mar
24
comment Resolutions of bimodules as $R^e$-modules.
Yes, it's just that when I read $R \otimes_{k} M \otimes_{k} R$ my tired eyes automatically read $\hom_{k}(R \otimes_{k} M \otimes_{k} R,N)$ :).
Mar
24
comment Resolutions of bimodules as $R^e$-modules.
It's "Hochschild homology" by Clas Lofwall.
Mar
24
comment Resolutions of bimodules as $R^e$-modules.
2 - Just to be clear you're considering $R \otimes_{k} M \otimes_{k} R$ as a left $R^e$-module in $\hom_{R^e}(R \otimes_{k} M \otimes_{k} R)$? I'm interested in $R \otimes R^{\otimes n} \otimes R$ as a left $R^e$-module, I basically want to know if $R$ projective as a $k$-module implies $R \otimes R^{\otimes n} \otimes R$ as a left $R^e$-module. I ask because I asked on MO if $R$ projective as a $k$-module implied $R$ projective as a $R^e$-module and that's not the case.
Mar
24
comment Resolutions of bimodules as $R^e$-modules.
Thank you, thank you so much! I'm really going to go for broke here and ask: 1 - Where did the isomorhpism $\hom_{R^e}(R \otimes_{k} M \otimes_{k} R, N) ≅ \hom_{k}(M,\bar{N})$ come from?
Mar
23
asked Resolutions of bimodules as $R^e$-modules.
Mar
23
awarded  Disciplined
Mar
1
comment Picturing resolutions of complexes
I hadn't seen this, thank you so much @Aaron.
Jan
1
asked Picturing resolutions of complexes
Aug
18
awarded  Supporter
Aug
14
revised Composition of derived functors and comparison between hypercohomology and sheaf cohomology
edited body
Aug
12
asked Composition of derived functors and comparison between hypercohomology and sheaf cohomology
Aug
9
comment Computing the hypercohomology of a complex of acyclic sheaves
Thanks @ZhenLin it seems that I may have found a way to compute it, thanks
Jul
29
comment Computing the hypercohomology of a complex of acyclic sheaves
Thanks, yes I know, and that's actually what I need the hypercohomology for, that's my end goal: to compute the cohomology of the complex of global sections by computing the hypercohomology. I do it because I asked what I should do to obtain the cohomology of the complex of global sections in case the only piece (or one of the few) information I had is that the sheaves are acyclic and they told me I should turn to hypercohomology, so kind of a circular reference, I don't know if there are other techniques to compute hypercohomology maybe? Thanks
Jul
28
awarded  Editor