3,265 reputation
529
bio website
location
age
visits member for 2 years, 11 months
seen Jan 21 at 15:19

Nov
15
comment Is the $\sigma$-finiteness condition necessary to ensure that $L^p(\mu)$ is reflexive?
It should be Folland's book. In addition, $L^1$ isn't reflexive in general even if $\mu$ is $\sigma$-finite, say, $(L^1(\mathbb R))^*=L^\infty(\mathbb R)$.
Nov
15
revised Any real analytic Frobenius theorem used in the proof of integrable almost complex manifolds to arise from complex manifolds?
edited tags; edited title
Nov
14
asked Is the $\sigma$-finiteness condition necessary to ensure that $L^p(\mu)$ is reflexive?
Nov
14
asked Any real analytic Frobenius theorem used in the proof of integrable almost complex manifolds to arise from complex manifolds?
Nov
14
revised $\left\{\,f\in L^1[0,1]\,\big\vert\,\int_0^1\lvert f\rvert^2>1\right\}$ is open
added 3 characters in body
Nov
14
revised $\left\{\,f\in L^1[0,1]\,\big\vert\,\int_0^1\lvert f\rvert^2>1\right\}$ is open
added 13 characters in body
Nov
14
revised $\left\{\,f\in L^1[0,1]\,\big\vert\,\int_0^1\lvert f\rvert^2>1\right\}$ is open
added 384 characters in body
Nov
14
asked $\left\{\,f\in L^1[0,1]\,\big\vert\,\int_0^1\lvert f\rvert^2>1\right\}$ is open
Oct
29
comment How to show that a measurable function on $R^d$ can be approximated by step functions?
@Groups Edited, thanks!
Oct
29
revised How to show that a measurable function on $R^d$ can be approximated by step functions?
deleted 2 characters in body
Oct
25
comment Proper and free action of a discrete group
Thanks a lot! It seems that Lee's book on smooth manifolds also takes this as definition.
Oct
25
accepted Proper and free action of a discrete group
Oct
25
asked Proper and free action of a discrete group
Oct
10
awarded  Nice Question
Sep
30
awarded  Explainer
Sep
11
comment Is every local ring a valuation ring?
But, $F$ isn't the field of fractions of $\{0,1\}\subseteq F$?
Sep
11
revised Is every local ring a valuation ring?
added 13 characters in body
Sep
11
revised Difference between two concepts of homotopy for simplicial maps?
added 69 characters in body
Sep
11
comment Difference between two concepts of homotopy for simplicial maps?
@ZhenLin It seems that you are right, if the definition of the product is essentially same as the one in Goerss & Jardine. It might be a mistranlation from Russian.
Sep
11
comment Difference between two concepts of homotopy for simplicial maps?
@QiaochuYuan Simply homotopy of $f,g\colon X\to Y$ here, informally speaking, is just a simplicial map $F\colon\Delta[1]\times X\to Y$ from a cylinder $\Delta[1]\times X$ (triangulated canonically, where $\Delta[1]$ is just the simplicial set associated with $I=[0,1]$, i.e., $1$-simplex) to $Y$, both of which are simplicial sets. Sorry for my ignorance. I don't know what you're referring to. Thanks, anyway.