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 2d awarded Good Answer Apr4 awarded Curious Sep30 awarded Explainer Sep24 awarded Autobiographer Sep4 comment Find a closed form for this sequence: $a_{n+1} = a_n + a_n^{-1}$ I guess positivity of $\varphi$ is one sufficient condition to get the correct behavior. Only a guess though. Aug4 awarded Yearling Mar12 comment Is $0$ a natural number? This question is not related to math, it is the consequence of an ambiguous notation which was used by Dedekind in 1888. To avoid ambiguity, ℕ* is used to exclude 0. I cannot manage to understand how this question is still not closed. Mar12 comment Simple combinatorics question - caught off guard! I see your point, yet I believe it is a shame to have ambiguous statements in math. Mar12 comment Simple combinatorics question - caught off guard! With Wiki, "there is no universal agreement about whether to include zero in the set of natural numbers: some define the natural numbers to be the positive integers {1, 2, 3, ...}, while for others the term designates the non-negative integers {0, 1, 2, 3, ...}. The former definition is the traditional one, with the latter definition having first appeared in the 19th century." In the context, this is ambiguous since "For natural numbers (taken to include 0) n and k", the binomial coef is defined Mar12 comment Simple combinatorics question - caught off guard! Not in my country. In France, we call ℕ* the set excluding 0. Mar12 comment Simple combinatorics question - caught off guard! This is wrong for n=0. Mar12 comment Simple combinatorics question - caught off guard! This is clear and intuitive. However, one would have to take care of the case for which a pair contains twice the same "menu" (n=0), and for which the statement is wrong. Jan26 comment Funny identities This one is amazing. Oct23 comment Why does the google calculator give tan 90 degrees = 1.6331779e+16? Thi is the result of dividing by a "zero" double. Aug4 awarded Yearling May7 awarded Caucus Apr30 comment Uniform distribution on a simplex via i.i.d. random variables Jan25 awarded Popular Question Nov24 awarded Nice Answer Nov23 revised Taking the limit under the integral sign. Help! Clearer title