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  • 0 posts edited
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  • 27 votes cast
Feb
17
revised Did I do this proof right?
Here is one proof.
Feb
12
awarded  Teacher
Feb
12
answered Did I do this proof right?
Feb
1
awarded  Critic
Feb
1
comment If $x_n \rightarrow 0$ and $\{y_n\}$ is a bounded sequence, then $x_ny_n \rightarrow 0$.
Just be careful of your $\alpha$. It must be a point so that $\alpha \in \mathbb{R}^+$. And yes, the same $N$ works because $y_n$ is bounded independent of whether $x_n$ converges or not.
Jan
12
accepted Part of Fubini's Theorem with almost everywhere
Jan
12
comment Part of Fubini's Theorem with almost everywhere
This question was already asked math.stackexchange.com/questions/1092685/…
Jan
12
accepted Tonelli and Fubini and almost everywhere
Jan
12
asked Part of Fubini's Theorem with almost everywhere
Jan
6
asked Riemann and Lebesgue improper integral Proof
Jan
6
revised Tonelli and Fubini and almost everywhere
added 65 characters in body
Jan
6
comment Tonelli and Fubini and almost everywhere
I had forgotten about this theorem. Thank you.
Jan
6
asked Tonelli and Fubini and almost everywhere
Jan
5
accepted Folland 2.36 portion of proof
Jan
5
comment Folland 2.36 portion of proof
This is the conclusion I arrived at as well. Thank you!
Jan
5
asked Folland 2.36 portion of proof
Dec
22
accepted Question about simple functions as described in Folland's Real Analysis
Dec
22
comment Question about simple functions as described in Folland's Real Analysis
I'm a fool. Thank you so much.
Dec
22
comment Question about simple functions as described in Folland's Real Analysis
Yes, I understand that part of the proof. My question is why does this proof work for the more general case. I'm not seeing why $\phi$ being simple and 0 almost everywhere imply that it's integral is 0 since this is something we are trying to prove in the first place.
Dec
21
asked Question about simple functions as described in Folland's Real Analysis