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Dec
17
revised Approximating Distribution of a Data Set
fixed speling in title
Dec
17
comment $\sum_{n=1}^{\infty}\frac{H_n}{n^2 2^n}=\zeta(3)-\frac{1}{2}\log(2)\zeta(2)$
+1. Nice, Rob! The factor of $2^n$ in the denominator made me think of the Euler series transformation, too, but I couldn't make it go through. Also, your work starting from equation (13) is an evaluation of $A(2,1)$ from my question here, which means you've got a derivation for the last of the three sums from that question. I'd be happy if you were willing to finish off your series of answers to my question with your derivation for $A(2,1)$ here.
Dec
17
comment Infinite Series $\sum_{n=1}^\infty\frac{H_{2n+1}}{n^2}$
@RaymondManzoni: You're welcome. It was one of those questions where the quality of the answers far exceeded my expectations!
Dec
16
comment Infinite Series $\sum_{n=1}^\infty\frac{H_{2n+1}}{n^2}$
+1. For a different evaluation of $S(-1)$ that relies solely on manipulation of the summation, see robjohn's answer here.
Dec
16
revised The $n^{th}$ root of the geometric mean of binomial coefficients.
edited tags
Dec
15
awarded  Necromancer
Dec
3
revised Number of elements of $3n$ binary tuples, where the ordinates add up to $2n$.
fixed grammar
Dec
3
answered Number of elements of $3n$ binary tuples, where the ordinates add up to $2n$.
Nov
26
awarded  Enlightened
Nov
26
awarded  Nice Answer
Nov
20
awarded  Popular Question
Nov
19
comment Why is $1^{\infty}$ considered to be an indeterminate form
@Mehrdad: You should ask that as a question on the main site.
Nov
15
awarded  Popular Question
Nov
12
awarded  Announcer
Nov
7
awarded  Popular Question
Oct
30
comment A recurrence relation for Stirling numbers (2nd kind)
I asked a question about the same sum here. There are lots of different results about this sum in the question and answers there.
Oct
18
awarded  Announcer
Oct
7
awarded  Yearling
Oct
7
awarded  Nice Answer
Oct
2
comment How this operation is called?
I wrote a paper a few years ago that uses finite differences to evaluate binomial sums. Since the finite difference is $S(a_n) - a_n$, some of the ideas in there are related to your observation here. In case you're interested, the paper is here.