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  • 0 posts edited
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  • 33 votes cast
Mar
3
asked Find $\int e^{2\theta} \cdot \sin{3\theta} \ d\theta$
Mar
3
accepted Choices for Integrationg by Parts
Mar
3
comment Choices for Integrationg by Parts
Errummm.... that was silly mistake. Ok, that was my problem! Thank you for pointing that out Mike! How could I have missed that?
Mar
3
comment Choices for Integrationg by Parts
If that is the case, then shouldn't the answer come out the be the same, regardless of what (within reason) I pick?
Mar
3
comment Choices for Integrationg by Parts
Thank Mike, but I did use v and du in the integral. Since I used integration by parts twice, maybe that is why it looks as though I had done that.
Mar
3
asked Choices for Integrationg by Parts
Mar
2
accepted Methodology for Integration by Parts
Mar
2
comment Methodology for Integration by Parts
Ah... good point, Antonio.
Mar
2
comment Methodology for Integration by Parts
Ah ha! Thank you for answering my second question! I figured that was why they chose $\sin{x}$ over $\sin^{n - 1}{x}$, but I just wanted to be sure that I wasn't missing some mathematical rule. Do you know why they decided to split up $\sin^{n}{x}$ into two terms and then let dv be $\sin{x} \ dx$ rather than the understood 1?
Mar
2
comment Methodology for Integration by Parts
Hmm... yes, but then I would like an explanation as to why the other methods wouldn't work.
Mar
2
asked Methodology for Integration by Parts
Feb
24
accepted Integrating $\int \sin^n{x} \ dx$
Feb
24
accepted Integrate $\csc^3{x} \ dx$
Feb
24
comment Integrate $\csc^3{x} \ dx$
Thank you for your help, Arturo! +1 answer accepted!
Feb
24
asked Integrate $\csc^3{x} \ dx$
Feb
24
awarded  Commentator
Feb
24
comment Integrating $\int \sin^n{x} \ dx$
... and Gerry!!
Feb
24
comment Integrating $\int \sin^n{x} \ dx$
ohhh... then the $(n - 1)$ was distributed when the integral was broken up, I guess that is what was throwing me off. Thanks, Mike!
Feb
24
revised Integrating $\int \sin^n{x} \ dx$
added 70 characters in body
Feb
24
asked Integrating $\int \sin^n{x} \ dx$