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  • 0 posts edited
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  • 33 votes cast
Nov
5
asked Combinatorics: When To Use Different Counting Techniques
Oct
17
awarded  Popular Question
Oct
11
comment Pythagorean theorem: $A^2 + A^2 = C^2$ How to solve for $A$?
@Campbeln Not a problem! If you found my answer helpful, could you accept the answer, please?
Oct
11
accepted How is $2 + e^{t^2} - e^{-t^2}$ Equal to $(e^t + e^{-t})^2$?
Oct
11
comment How is $2 + e^{t^2} - e^{-t^2}$ Equal to $(e^t + e^{-t})^2$?
Oh... Thank you for making that clear. The \frac{e^t}{e^t} cancel to give one. That is clear in the way you broke it up. Unfortunately, I was given the longer expression to start with, and had to see if it simplified, so I didn't have the opportunity to work backwards.
Oct
11
comment How is $2 + e^{t^2} - e^{-t^2}$ Equal to $(e^t + e^{-t})^2$?
@AustinMohr Yep, I made a silly typo.
Oct
11
revised How is $2 + e^{t^2} - e^{-t^2}$ Equal to $(e^t + e^{-t})^2$?
added 15 characters in body
Oct
11
answered Pythagorean theorem: $A^2 + A^2 = C^2$ How to solve for $A$?
Oct
11
asked How is $2 + e^{t^2} - e^{-t^2}$ Equal to $(e^t + e^{-t})^2$?
Aug
15
awarded  Autobiographer
Mar
15
comment Divide with remainder $\frac{x^2}{x^2 + x + 2}$
Woo-hoo! Just what I was looking for! Thank you, Arturo!
Mar
15
accepted Divide with remainder $\frac{x^2}{x^2 + x + 2}$
Mar
14
accepted Why Doesn't This Integral $\int \frac{\sqrt{x^2 - 9}}{x^2} \ dx$ Work?
Mar
14
accepted Equivalent to $\begin{align}\int \cos{\left(2x\right)} \ dx\end{align}$?
Mar
14
asked Divide with remainder $\frac{x^2}{x^2 + x + 2}$
Mar
14
accepted Find $\int e^{2\theta} \cdot \sin{3\theta} \ d\theta$
Mar
14
comment Equivalent to $\begin{align}\int \cos{\left(2x\right)} \ dx\end{align}$?
Thank you all!!
Mar
14
comment Equivalent to $\begin{align}\int \cos{\left(2x\right)} \ dx\end{align}$?
@anon You'd have to dig around to find what I'm references.
Mar
14
asked Equivalent to $\begin{align}\int \cos{\left(2x\right)} \ dx\end{align}$?
Mar
12
comment Integration: How to Begin?
Hmm... how can we stop thinking in terms of right triangles if the above example uses $\tan{x}$ and $\cos{x}$? Plus, by having a square root, we easily know that it would (in this case) exist as the hypotenuse of the triangle.