# Gigili

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bio website location age member for 3 years, 3 months seen Jul 27 at 9:56 profile views 2,459

I write to discover what I think.

# 1,623 Actions

 May6 answered Limit to infinity question May6 revised WolframAlpha blows simple substitution? improved formatting May6 suggested suggested edit on WolframAlpha blows simple substitution? May6 revised WolframAlpha blows simple substitution? improved TeX and formatting May6 revised Measure theory : Almost Everywhere improved formatting May6 suggested suggested edit on Measure theory : Almost Everywhere May6 suggested suggested edit on WolframAlpha blows simple substitution? May6 comment Understanding the relationship between differentiation and integration Great answer, Peter. May5 comment @Phira: I was a 4k user there (the 6th user or so, as the site is on beta and quite new) but deleted my account due to some unexpected events. May5 comment Oriented trees and ordered trees It might be more helpful to explain more details instead of only the definitions. May5 revised Piece-wise linear interpolating polynomials improved formatting and TeX, edited tag May5 suggested suggested edit on Piece-wise linear interpolating polynomials May5 revised continuous functions on $\mathbb R$ such that $g(x+y)=g(x)g(y)$ improved formatting, edited tag May5 suggested suggested edit on continuous functions on $\mathbb R$ such that $g(x+y)=g(x)g(y)$ May5 revised percentage calculation improved TeX and formatting May5 suggested suggested edit on percentage calculation May5 revised Why do we divide the expectation of the indicator function times X by P(B) for E[X|B]? improved TeX May5 suggested suggested edit on Why do we divide the expectation of the indicator function times X by P(B) for E[X|B]? May4 comment Find $p(B)$ given $P(A)$, $P(A\cup B)$, and one more piece of information @mastergoo: 1) $1/3=1/4+p$ , 2) $1/3=1/4+p+p/4$ , 3) ... _ The main formula is $P(A \cup B)=P(A)+p(B)−P(A \cap B)$ and you substitute $P(A \cap B)$ with what I said in each part! May4 comment Find $p(B)$ given $P(A)$, $P(A\cup B)$, and one more piece of information I suspect the other one was wrong as well, you need to be more careful.