Gigili

3,153 reputation

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One Hour Translation provides High quality, Fast, 24x7 Professional Human Translation at competitive fixed price of over 57 languages and over 2000 language pairs. They are able to provide high-quality translations around the clock, any day, any time thanks to a community of over 10000 Professional Translators from over 100 different countries.

I write to discover what I think.

	3,153 reputation	bio	website		visits	member for	1 year, 11 months
825 badges		location			seen	8 hours ago

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Dec 26	comment	Using power series, compute: $\sum\limits_{1}^{\infty}\frac{n}{2^n}$ @Alex: Now it looks great, thank you.
Dec 26	comment	Using power series, compute: $\sum\limits_{1}^{\infty}\frac{n}{2^n}$ I recommend you to use double dollar sign to make it more readable. I can hardly follow the steps. Anyway, +1.
Dec 25	comment	Solving $z^4 + 2z^3 + 6z - 9 = 0$ @Tim: Right, I made a small mistake there. Thank you.
Dec 25	revised	Solving $z^4 + 2z^3 + 6z - 9 = 0$ added 126 characters in body
Dec 20	revised	Power of prime ideal corrected typos and edited tag
Dec 20	suggested	suggested edit on Power of prime ideal
Dec 20	revised	Some three consecutive numbers sum to at least $32$ edited tag
Dec 20	suggested	suggested edit on Some three consecutive numbers sum to at least $32$
Dec 19	revised	Solving $z^4 + 2z^3 + 6z - 9 = 0$ added 89 characters in body
Dec 19	answered	Solving $z^4 + 2z^3 + 6z - 9 = 0$
Dec 19	revised	Non-linear ODE: $(y')^2 + y = xy'$ improved formatting
Dec 19	suggested	suggested edit on Non-linear ODE: $(y')^2 + y = xy'$
Dec 19	comment	Non-linear ODE: $(y')^2 + y = xy'$ @H.M.Šiljak: Eh, how so? It should be $(y')^2 + y = xy'$ as OP mentioned.
Dec 19	revised	Shortest Confidence interval for $\beta^2$ improved formatting
Dec 19	suggested	suggested edit on Shortest Confidence interval for $\beta^2$
Dec 19	comment	Non-linear ODE: $(y')^2 + y = xy'$ @H.M.Šiljak: I think you meant this one.
Dec 19	accepted	Searching a binary search tree for a specific value
Dec 19	asked	Searching a binary search tree for a specific value
Dec 19	comment	Confusing conditional probability question @Nana: Got it, thanks. I'd +1 it again if given the chance.
Dec 19	comment	Confusing conditional probability question @Nana: I think when we know the probability of the first item, then we should calculate the probability without it for the rest of sampled items. Like the case 99 items is taken. Am I right?