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visits member for 2 years, 2 months
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Jan
25
comment Are transcendental numbers dense in $\mathbb R$? What is algebraic number? Is $cos(\pi/13)$ algebraic?
try using \cos instead of just cos in the edit.
Jan
25
asked Quarternionic Analysis
Jan
25
revised Integrating $\int_0^\infty\frac{\log (1+z^2)}{e^z-1}dz$ using residue calculus.
deleted 3 characters in body
Jan
25
revised Integrating $\int_0^\infty\frac{\log (1+z^2)}{e^z-1}dz$ using residue calculus.
deleted 88 characters in body
Jan
25
revised Integrating $\int_0^\infty\frac{\log (1+z^2)}{e^z-1}dz$ using residue calculus.
added 7 characters in body
Jan
25
revised Integrating $\int_0^\infty\frac{\log (1+z^2)}{e^z-1}dz$ using residue calculus.
added 54 characters in body
Jan
24
asked Integrating $\int_0^\infty\frac{\log (1+z^2)}{e^z-1}dz$ using residue calculus.
Jan
24
revised Express $\sin nx$ and $\cos nx$ in terms of $\sin x$ and $\cos x$ respectively
added 133 characters in body
Jan
24
answered Express $\sin nx$ and $\cos nx$ in terms of $\sin x$ and $\cos x$ respectively
Jan
24
comment Proof of an equality involving cosine
This may help: Try taking $n=1$, $n=2$, $n=3$, ... in each case; see if you can prove for small $n$ first. You may be able to use proof by induction...
Jan
22
comment What is known about doubly exponential series?
Functions of this form can have what are called natural barriers which basically means that such functions cannot be analytically continued past their radius of convergence.
Jan
22
awarded  Yearling
Jan
20
comment How to calculate with absolute value.
There are two cases: (1) $x\geq 0$ and (2) $x<0$. You could consider each separately.
Jan
20
revised proof of function being not continuous
changed lim to \lim. Changed 2 to two as it wouldn't let me save the edits without an extra 3 characters :-S
Jan
20
suggested suggested edit on proof of function being not continuous
Jan
20
comment Why the identity $ a^x = a^y \Longrightarrow x=y $ do not work for $a<0$?
what if $x$ is complex?
Jan
17
revised How to sum this divergent series to 1/2?
added 67 characters in body
Jan
17
answered How to sum this divergent series to 1/2?
Jan
16
comment Choice of branches for contour integration.
@Harold what if the function was instead $f(z)=1/(z^2+1)^{1/2}$. I'm guessing we could not use a keyhole contour as described in my last comment because, although a full rotation would "cancel", at the same time we get singularities. Is this correct?
Jan
16
awarded  Civic Duty