1,758 reputation
517
bio website
location
age
visits member for 2 years, 3 months
seen 13 mins ago

2h
comment Standard notation for the indicator function of the odd integers
I think I'll use $\chi_{2\mathbb{Z}+1}(x)$ then. Thanks.
2h
asked Standard notation for the indicator function of the odd integers
1d
awarded  Popular Question
2d
revised Evaluate $\int_a^s\frac{(t-s)^n}{t(t-z)^{n+1}}dt.$
added 138 characters in body
2d
revised Evaluate $\int_a^s\frac{(t-s)^n}{t(t-z)^{n+1}}dt.$
edited title
2d
revised Evaluate $\int_a^s\frac{(t-s)^n}{t(t-z)^{n+1}}dt.$
edited body
2d
comment Evaluate $\int_a^s\frac{(t-s)^n}{t(t-z)^{n+1}}dt.$
@Claude - it's $s$; I've corrected the title.
2d
revised Evaluate $\int_a^s\frac{(t-s)^n}{t(t-z)^{n+1}}dt.$
edited title
2d
asked Evaluate $\int_a^s\frac{(t-s)^n}{t(t-z)^{n+1}}dt.$
Apr
15
comment Optimization issue, how to obtain the maximal value?
@user14002 Do you know about www.coursera.org ? If you search for the "Calculus One" course there is a whole video section about "Optimization" which will help you find your maximum.
Apr
14
comment Finding argument of a complex number
Since a complex number can be plotted on the plane, you can draw a line from the origin to the point and use $\tan$ to obtain the angle the line makes with the positive real axis.
Apr
14
comment Optimization issue, how to obtain the maximal value?
@user143002 I don't have time right now, but will take a look later unless someone else does. One tip: let $B=0$ and try to solve. Then let $B=1$ and try to solve, and so on. You may see a pattern arise !
Apr
14
comment Optimization issue, how to obtain the maximal value?
You could try to simplify first, e.g. since $N$ and $B$ are identified positive integers, then ${N+B\choose B}$ can be replaced by a constant, $\lambda$, say. You may also be able to simplify the sum in the denominator using the Binomial Theorem somehow.
Apr
5
awarded  Necromancer
Mar
29
awarded  Nice Question
Mar
26
comment Necessary/sufficient conditions for an infinite product to be exactly equal to $1$
@GerryMyerson - so we just take logs and apply the usual tools?
Mar
26
accepted Why does this product diverge?
Mar
26
comment Why does this product diverge?
Ok, thanks all I think I've cleared this up now. Basically it all depends on what we mean by an infinite product. Using the standard "sequence of partial products" then we have divergence, but if we explicitly state @Sabyasachi's intention, $$\lim_{n\to\infty}\prod_{k=1}^{2n}a_n,$$ then we have convergence. Delicate!
Mar
26
comment Why does this product diverge?
This is where I misunderstand. The upper index in the product is always $2n$, so by definition the product is never defined with an upper index of $2n+1$. Maybe this is one of those "murky" $\infty$ areas since $\infty$ is not a natural number? ...
Mar
26
asked Why does this product diverge?