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May
6
awarded  Caucus
Apr
25
revised What is the polar form of $ z = 1- \sin (\alpha) + i \cos (\alpha) $?
added 2 characters in body
Apr
25
answered What is the polar form of $ z = 1- \sin (\alpha) + i \cos (\alpha) $?
Apr
18
awarded  Disciplined
Apr
14
comment A question about the residue calculus
Is this integral even convergent?
Mar
28
answered Maximum value of $Z$
Mar
11
comment How do I calculate the sum of $\sum_{k=1}^{\infty}\frac{(2-x)^k}{2^k\cdot k}$ in every x in (0, 4)?
@vonbrand Yes it is, so what's your point?
Mar
11
answered How do I calculate the sum of $\sum_{k=1}^{\infty}\frac{(2-x)^k}{2^k\cdot k}$ in every x in (0, 4)?
Mar
11
answered Graph of a curve
Mar
11
comment Graph of a curve
what have you tried?
Feb
27
comment Is this an even function?
It isn't because $f(-x)=3+x\ne 3-x=f(x)$ for every $x \in [-1,0)\cup(0,1]$.
Feb
23
comment Prove that $\int_0^{\infty} \frac{\sin(2013 x)}{x(\cos x+\cosh x)}dx=\frac{\pi}{4}$
@MartinGales I think you are mixing things up, it is clear that the series $\sum_{k=1}^\infty(-1)^{k-1}$ does not converge, and I'm surprised you still believe it does. In fact, a necessary condition for the convergence of a series $\sum_{k=1}^\infty a_k$ is that $a_k \to 0$ which obviously is not satisfied.
Feb
21
comment Prove that $\int_0^{\infty} \frac{\sin(2013 x)}{x(\cos x+\cosh x)}dx=\frac{\pi}{4}$
@MartinGales I still don't see why the sum should be $1/2$. Are you using some "advanced calculus" to prove it? All I can see is that $s_{2n}=0$ and $s_{2n+1}=1$, and with my current knowledge of calculus, the latter tells me that this sum does not exist.
Feb
20
comment Prove that $\int_0^{\infty} \frac{\sin(2013 x)}{x(\cos x+\cosh x)}dx=\frac{\pi}{4}$
@MartinGales Yes, that's true only for $|x|<1$.
Feb
18
comment Prove that $\int_0^{\infty} \frac{\sin(2013 x)}{x(\cos x+\cosh x)}dx=\frac{\pi}{4}$
How do you prove that $\sum_{k=1}^\infty(-1)^{k-1}=\frac12$ although the partial sum $s_n:=\sum_{k=1}^n(-1)^{k-1}=(1-(-1)^n)/2$ does not converge?
Feb
18
comment Evaluation by methods of complex analysis $\int_{0}^{1} \frac{\ln(x+1)}{x^2+1} \mathrm{dx}$
@MårtenW I like the figure, which program did you use to draw it?
Feb
16
answered Find a closure of the set
Feb
16
answered Equality of 2 integrals (complex)
Feb
15
revised general solution to $u'=\left(\begin{matrix} -1 & 1\\ 0 & -1 \end{matrix}\right)u$.
added 352 characters in body
Feb
15
revised general solution to $u'=\left(\begin{matrix} -1 & 1\\ 0 & -1 \end{matrix}\right)u$.
edited body