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location Göttingen
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visits member for 2 years, 6 months
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Apr
25
comment If G is a finite abelian group and $a_1,…,a_n$ are all its elements, show that $x=a_1a_2a_3…a_n$must satisfy $x^2=e$.
What you have defined is obviously not a group. E.g. you've already seen that 22=6=42, but then (22)3=(42)3 and -- if associativity would hold -- 2=4.
Apr
9
comment Equivalence relation: prove that $(X \cap Y) $\ $E $ $\subset (X$ \ $E) \cap (Y$ \ $E)$
Are you sure that you have written the inclusion in the right direction?
Apr
9
comment How do I find arccos(-16.503)
So, the problem seems to lie in an earlier step. How did you arrive at the expression $\arccos(-16.503)$?
Apr
4
comment cartesian product $A^2 = A$, possible?
Am I missing something, or should it be $A_\omega\times A_\omega\subset A_\omega$?
Apr
3
comment Limit definition by ordinal numbers
Principia Mathematica, *207: "A term x is said to be the "upper limit" of alpha in P if alpha has no maximum and x is the sequent of alpha. In this case, x immediately follows the class alpha, though there is no one member of alpha with x immediately follows."
Apr
2
comment Can two function $f$ and $g$ have same values through out a given interval and different values outside that interval?
@user136561: This merely shows the difference (within a certain interval) is smaller than the resolution of the computer monitor.
Apr
1
comment Why does $f(x)=ax^2 + bx + c \ge 0\ \forall x \in \mathbb R$ imply $f$ has at most one real distinct root and discriminant $D \le 0$?
@Sabyasachi: Take $a=1$, $b=c=0$.
Mar
31
comment proving that $f:\mathbb N\to\mathbb N\times\mathbb N$ is countable using Cantor's diagonal method
Sorry for the terrible punctuation in my comment above. $f$ may be defined as $\{(n,f(n)): n\in\mathbb N\}$.
Mar
31
comment proving that $f:\mathbb N\to\mathbb N\times\mathbb N$ is countable using Cantor's diagonal method
This set of functions, i.e. $(\mathbb N\times\mathbb N)^\mathbb N$ certainly is not countable. You can use Cantor's diagonal method to prove that. Note that <i>the set of functions</i> and <i>the function</i> (which one) are different concepts. A function $\mathbb N\to\mathbb N$ can be defined as a set (of pairs $(n,f(n)$, and this would indeed be countable. But this is almost certainly not what you want to know. Could you edit the question to incorporate answers you gave in the comments?
Mar
28
comment Show from the axioms: Addition in a quasifield is abelian
@azimut: Thanks, I've added the answer accordingly, fixing an incorrect eq reference along the way.
Mar
25
comment Is there any number $n$ such that $nm=0$, $n\neq 0$, and $m\neq 0$?
@YiyuanLee: It is not a group but merely a monoid (there are no zero divisors in a group since they do not have an inverse). The group $(ℤ/6ℤ)^*$ exists, but it does not contain the elements 2 and 3.
Feb
14
comment Why is $(0,0,0)$ not acceptable as a co-ordinate on the projective plane?
In other words, the points of the projective plane are the one-dimensional subspaces of a three-dimensional vector space. Any of these subspaces can be uniquely identified by a basis vector (so we can write $(x,y,z)$); but $(0,0,0)$ is not a basis vector, and it does not identify a one-dimensional subspace.
Jan
27
comment Exercise regarding boolean algebra?
Hint: a) use X+(YZ)=(X+Y)(X+Z)
Sep
12
comment Blue eyes: a logic puzzle
I do not think that the claim marked * is true. Consider the case where the guru announces "98 people who have blue eyes": everyone has known this before (universal knowledge), because everyone sees at least 99 blue-eyed people. Moreover, everyone knows that everyone knows: blue-eyed people see 99 other blue-eyed people, so these must each see at least 98 blue-eyed people. But there it stops. It is not true that everyone knows that everyone knows that everyone knows that the guru sees 98 blue-eyed people. This, however, is a necessary condition for "common knowledge".
Feb
20
comment Number of zeros in a number
Shouldn't the input encoding be part of the problem statement?
Jan
28
comment Can an event be possible if its probability is zero?
You do not even need look for repeated numbers -- the probability of generating any given number is zero (assuming a true random-number generator and infinite precision). Still it happens every time the generator is run.
Jan
15
comment Is $f = x^2$ or only $f(x) = x^2$ correct?
It is certainly quite common in physics to omit function arguments; but note that the two notations you give for kinetic energy are not equivalent: E.g. for a rocket, the complete expression would be $E(t)=\frac{1}{2}m(t)v^2(t)$ since mass is not constant.
Jun
7
comment Is it generally accepted that if you throw a dart at a number line you will NEVER hit a rational number?
I think it is important that the author says it will not happen, not that it cannot happen. So, it is not impossible, it just is not going to happen... I think this is a nice way to explain probability zero, although not mathematically exact.
Feb
29
comment How many combinations of 6 items are possible?
Also, it is not clear whether the OP wants to count reordered sequences. The use of sets hints at no, but the second example given is (on purpose?) not increasing.
Feb
20
comment Delta function integral
Am I missing something, or should it be $E-E_S$ in the integrand?