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	1,386 reputation	bio	website		visits	member for	1 year, 4 months
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May 8	asked	The definition of 1-quotient map in functional analysis
May 7	awarded	Caucus
Apr 30	comment	Unbounded self- adjoint and von Neumann algebra @MartinArgerami any idea for this question
Apr 29	comment	Unbounded self- adjoint and von Neumann algebra @MartinArgerami see the end of the question
Apr 29	asked	Unbounded self- adjoint and von Neumann algebra
Apr 14	comment	Unbounded operator $T $ is bounded below when $\overline T$ is bounded Since T is unbouneded,how can u use that crucial fomular
Apr 14	accepted	The Kernel of unbounded operator in Hilbert space
Apr 14	asked	The direct sum of self-ajoint operators
Apr 13	comment	Spectrum of differentiation operator on $H=L^2[0,1]$ @ChristopherA.Wong $e^{\lambda x}$
Apr 13	comment	The Kernel of unbounded operator in Hilbert space sorry, i know it is a little rude,but can u see this question.math.stackexchange.com/questions/359064/…
Apr 13	comment	The Kernel of unbounded operator in Hilbert space maybe i need u help again.i search the website and can just find the case of idf/dx.math.stackexchange.com/questions/359064/…
Apr 12	asked	Spectrum of differentiation operator on $H=L^2[0,1]$
Apr 11	comment	Unbounded operator $T $ is bounded below when $\overline T$ is bounded @julien any clue for this problem
Apr 11	revised	Unbounded operator $T $ is bounded below when $\overline T$ is bounded added 7 characters in body
Apr 11	comment	Unbounded operator $T $ is bounded below when $\overline T$ is bounded @julien en.wikipedia.org/wiki/Unbounded_operator#CITEREFPedersen1989
Apr 11	comment	Unbounded operator $T $ is bounded below when $\overline T$ is bounded @julien $c\in R$
Apr 11	comment	The Kernel of unbounded operator in Hilbert space i don't understand why we can do $(x,T^*Tx)=(Tx,Tx)$
Apr 11	comment	The Kernel of unbounded operator in Hilbert space thks.I am also struggling with this math.stackexchange.com/questions/357257/… u give me some hint?
Apr 11	asked	The Kernel of unbounded operator in Hilbert space
Apr 10	asked	Unbounded operator $T $ is bounded below when $\overline T$ is bounded