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seen Jun 11 at 21:24

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awarded  Yearling
Aug
28
accepted Power series: Is the radius of convergence $\frac{1}{3}$ for $ \frac{x}{1\cdot3} + \frac{x^2}{2\cdot3^2} + \frac{x^3}{3\cdot3^3}+…$
Aug
28
comment Power series: Is the radius of convergence $\frac{1}{3}$ for $ \frac{x}{1\cdot3} + \frac{x^2}{2\cdot3^2} + \frac{x^3}{3\cdot3^3}+…$
Don't know :). I thought thats the way. In the results from the exercises, nowhere is a $x$. If I keep the $x$ everything is fine? Sorry for editing.
Aug
28
comment Power series: Is the radius of convergence $\frac{1}{3}$ for $ \frac{x}{1\cdot3} + \frac{x^2}{2\cdot3^2} + \frac{x^3}{3\cdot3^3}+…$
Pleas also see my Summery. I really want understand the stuff!
Aug
28
revised Power series: Is the radius of convergence $\frac{1}{3}$ for $ \frac{x}{1\cdot3} + \frac{x^2}{2\cdot3^2} + \frac{x^3}{3\cdot3^3}+…$
added 299 characters in body
Aug
28
comment Power series: Is the radius of convergence $\frac{1}{3}$ for $ \frac{x}{1\cdot3} + \frac{x^2}{2\cdot3^2} + \frac{x^3}{3\cdot3^3}+…$
I did nearly the same as Legendre. Is it not correct because I missed the $x$? Why did I used an incorrect hybrid? I just did $$\frac{1}{(n+2) \cdot 3{n+2}} \cdot \frac{(n+1) \cdot 3^{n+1}}{1}$$. I’m really sorry to be slow off the mark..
Aug
28
comment Power series: Is the radius of convergence $\frac{1}{3}$ for $ \frac{x}{1\cdot3} + \frac{x^2}{2\cdot3^2} + \frac{x^3}{3\cdot3^3}+…$
Ok. I asked because I’m a little bit confused. In my formulary is written: $r = \lim\limits_{n \to \infty} \left| \frac{a_n}{a_{n+1}} \right| $. In the exercises from the institute they use: $\lim\limits_{n \to \infty} \left| \frac{a_{n+1}}{a_n} \right| $. I used the second way. I’m quite aware where’s the different. With the second way I get the value for which the $\left| x \right|$ the power series is convergence, right?
Aug
28
comment Power series: Is the radius of convergence $\frac{1}{3}$ for $ \frac{x}{1\cdot3} + \frac{x^2}{2\cdot3^2} + \frac{x^3}{3\cdot3^3}+…$
So I have to inverse the result?
Aug
28
asked Power series: Is the radius of convergence $\frac{1}{3}$ for $ \frac{x}{1\cdot3} + \frac{x^2}{2\cdot3^2} + \frac{x^3}{3\cdot3^3}+…$
Aug
28
revised Why $ \lim_{n \rightarrow \infty}\frac{(5n^3-3n^2+7)(n+1)^n}{n^{n+1}(n+1)^2} =5e$?
edited title
Aug
28
comment Why $ \lim_{n \rightarrow \infty}\frac{(5n^3-3n^2+7)(n+1)^n}{n^{n+1}(n+1)^2} =5e$?
Thanks very much. I will keep in my mind. Wish a nice day.
Aug
28
revised Why $ \lim_{n \rightarrow \infty}\frac{(5n^3-3n^2+7)(n+1)^n}{n^{n+1}(n+1)^2} =5e$?
deleted 1 characters in body
Aug
28
accepted Why $ \lim_{n \rightarrow \infty}\frac{(5n^3-3n^2+7)(n+1)^n}{n^{n+1}(n+1)^2} =5e$?
Aug
28
revised Why $ \lim_{n \rightarrow \infty}\frac{(5n^3-3n^2+7)(n+1)^n}{n^{n+1}(n+1)^2} =5e$?
added 1 characters in body
Aug
28
revised Why $ \lim_{n \rightarrow \infty}\frac{(5n^3-3n^2+7)(n+1)^n}{n^{n+1}(n+1)^2} =5e$?
edited body
Aug
28
comment Why $ \lim_{n \rightarrow \infty}\frac{(5n^3-3n^2+7)(n+1)^n}{n^{n+1}(n+1)^2} =5e$?
Yes, Wolframalpha told me too :) I changed my Edit.
Aug
28
comment Why $ \lim_{n \rightarrow \infty}\frac{(5n^3-3n^2+7)(n+1)^n}{n^{n+1}(n+1)^2} =5e$?
Ok. Thanks. Pleas see my Edit. Does I understand it correctly? Greetz.