user1131467

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bio website location Zurich, Switzerland age member for 1 year, 4 months seen yesterday profile views 97

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 Oct26 comment How is $dx \over dy$ different from $\partial x \over \partial y$?But for all mechanical purposes all the same rules apply in both cases? We are asking how the "numerator" variable varies with respect to the "denomiator" variable, assuming everything else is held constant. Oct26 revised How is $dx \over dy$ different from $\partial x \over \partial y$?edited title Oct26 comment How is $dx \over dy$ different from $\partial x \over \partial y$?So what does $dx \over dz_1$ mean? Or is it undefined? If it is undefined why not just use the same notation? Oct26 asked How is $dx \over dy$ different from $\partial x \over \partial y$? Oct16 asked Any simplification of $\log_e{(1+e^x)}?$ Oct15 answered Generously Feasible? Oct15 comment Generously Feasible?Can you provide the link? It doesn't show in my search results? Oct15 asked Generously Feasible? Sep29 accepted Combinations of resistor networks? Sep25 revised Combinations of resistor networks?added 97 characters in body Sep25 asked Combinations of resistor networks? Sep21 comment Counting Hexagons in Triangle Grid Recurrence?@BrianM.Scott: What was your technique? Sep17 awarded Benefactor Sep17 accepted Counting Hexagons in Triangle Grid Recurrence? Sep17 comment Counting Hexagons in Triangle Grid Recurrence?This is correct, thanks. I was fooled by the N=4 case into thinking that all hexagons that touch all three sides must have one side of n-2, which is true for N=4 but not true for higher values of N. For example for N=5 we can have a hexagon that results from chopping off triangles of side 2 removed from each corner of the grid. Sep16 revised Counting Hexagons in Triangle Grid Recurrence?added 114 characters in body Sep16 awarded Promoter Sep14 asked Counting Hexagons in Triangle Grid Recurrence? Sep8 accepted N unlabelled balls in M labeled buckets Sep8 comment N unlabelled balls in M labeled bucketsThis proves it incorrect, however I still don't see what went wrong in my reasoning. The number of ways to put N labelled balls in M labelled buckets is $M^N$ correct? So why can't I just divide by the number of permutations of N balls to arrive at the unlabelled ball case?