43,936 reputation
33181
bio website uregina.ca/science/mathstat/…
location Regina, Canada
age 46
visits member for 2 years, 11 months
seen 20 hours ago

I'm an Operator Algebraist (which interestingly makes me an analyst!)


Dec
8
revised Justify with Proper Reason which among these is correct?
edited tags
Dec
8
answered How to show that $u^\ast$ is linear
Dec
7
answered The cone over separable C*-algebra is also separable?
Dec
7
answered confusing definition of lim sup
Dec
7
comment Two questions about orthogonal projections on Hilbert space
1. Because $P_MTP_M\to T $ strongly; as the limit $T $ is compact, the convergence is uniform (i.e. in norm). 2. No.
Dec
7
answered Two questions about orthogonal projections on Hilbert space
Dec
6
answered The set of all normal operators on a Hilbert space is not strongly closed
Dec
5
revised Triangular forms with a unitary matirx M
edited body
Dec
4
comment Toeplitz Operator is compact if and only if it has finite rank
Glad I could help.
Dec
4
revised How to create a linear set of proportions summing to 1?
edited tags
Dec
4
answered Existence of a approximate unit $U_{n}^{2}$ for a $ C^{*}$-algebra $
Dec
3
answered Toeplitz Operator is compact if and only if it has finite rank
Dec
3
comment How to learn math?
@LASH: you need to learn to study. To be disciplined and to train yourself. It looks like you have been able to go ahead by hacking your way through, because you have a talent for programming. But eventually you were going to hit the ceiling. Now the time to work hard has come.
Dec
3
answered Need countereample : If a sequence $(a_n) \in l^2 $ , then the sequence $(1/a_n) \notin l^2 $
Dec
2
answered Can an operator have spectrum consisting of just one point?
Dec
2
answered Types of von neumann algebras
Dec
2
answered Is a contraction idempotent operator self-adjoint?
Dec
1
comment Hilbert Spaces: Tensor Product
Yes. But a Hilbert space is in particular a complete Banach space. So you would have to argue that the formal space constructed like that is a complete Banach space with the norm induced by the inner product. It doesn't look simpler than taking the algebraic tensor product and completing it.
Dec
1
revised value of the norm of the trace mapping
deleted 1 character in body
Dec
1
answered Hilbert Spaces: Tensor Product