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| bio | website | mathematica.stackexchange.com |
|---|---|---|
| location | United States | |
| age | 36 | |
| visits | member for | 2 years, 7 months |
| seen | yesterday | |
| stats | profile views | 159 |
The gravitar was made with Mathematica, and inspired by this.
The contents of my posts are my own opinion, and do not reflect the opinions of my employer.
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May 6 |
awarded | Caucus |
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Jan 1 |
awarded | Excavator |
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Jan 1 |
revised |
Can we construct a Hilbert space where the operator $A_u v := -\frac{1}{2} v'' + (vF + v\int_\mathbb{R} Su + u\int_\mathbb{R} Sv )'$ is symmetric? changed apostrophe to ^\prime; spelling |
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Oct 3 |
awarded | Yearling |
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Jun 8 |
awarded | Constituent |
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Jun 8 |
awarded | Caucus |
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Apr 18 |
awarded | Promoter |
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Apr 16 |
asked | Generating the partners in a multi-dimensional irreducible representation. |
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Jan 30 |
comment |
Pythagorean Theorem Proof Without Words (request for words) Brilliant. Nice answer. |
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Nov 23 |
comment |
Compute $\mathbf v \mathbf A^{-1}\mathbf v^\top$ in a numerically stable way I found cholesky in the parallel directory: decompositions. |
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Nov 23 |
answered | Compute $\mathbf v \mathbf A^{-1}\mathbf v^\top$ in a numerically stable way |
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Nov 21 |
revised |
Finding the derivative of two integrals and establish their equality. reworded title |
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Nov 21 |
suggested | suggested edit on Finding the derivative of two integrals and establish their equality. |
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Nov 17 |
comment |
Possible bug in Mathematica? Also, Integrate doesn't do anything with an integer assumption (see the comments), so you have to watch out for them yourself. |
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Nov 17 |
comment |
Possible bug in Mathematica? Sorry, mixing messages there. $\int^\pi_{-\pi} \cos(qx) = 2$ when $q = 0$, but $0$ otherwise. But, you get the wrong answer if you integrate first and then set $q=0$. So, I was wondering if we're running into something similar with regards to $r$ in your integrals, but I didn't write it out as fully as I should have. |
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Nov 17 |
comment |
Possible bug in Mathematica? I have no idea why it ends being the exact negative. A guess is that like $\int^\pi_{-\pi} \cos(qx)$ with $q\in\mathbb{Z}$, there are multiple solutions depending on $r$, and by not fixing its value, Mathematica blithely chooses the incorrect one. |
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Nov 17 |
answered | Taking advantage of linearity of integration in Mathematica |
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Nov 17 |
comment |
Possible bug in Mathematica? Some quick notes. Symbolically integrating both pieces, I get (-i r^2 + r^(3/2) (i FresnelC[Sqrt[r]] + FresnelS[Sqrt[2]]))/Pi for $\int f$ and its negative for the second integral. However, integrating them both with a definite value of $r$, I get different results. For $r=5$, the sum is $1.19-5.00i$, and for $r=6$, the sum is $3.30-9.00i$, rounded, of course. I wonder if this is similar to the problem of integrating $\cos(q x)$ with $q \in \mathbb{Z}$. |
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Nov 16 |
comment |
How to solve integral in Mathematica? Can you do me a favor and give some details as to the mathematics problem you're trying to solve? If we can understand what it is you're trying to accomplish, we may be able to provide better answers. |
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Nov 16 |
comment |
How to make Runge-Kutta for solving nonlinear ODE system in Mathematica @George, I just downloaded your notebook, and in it you're using the form \[DifferentialD]f/\[DifferentialD]t which is incorrect as DifferentialD has no meaning by itself. Instead, you're looking for \[PartialD]. |
