301 reputation
12
bio website math.cas.cz/~jerabek
location Prague
age 35
visits member for 1 year, 4 months
seen 17 hours ago
stats profile views 15

I am a researcher at the Institute of Mathematics of the Czech Academy of Sciences. I work in the field of mathematical logic, specifically proof complexity (mainly subsystems of bounded arithmetic, but also propositional proof complexity) and nonclassical logics (admissible rules of modal, superintuitionistic, and other propositional logics).


Mar
6
comment Topological characterization of the closed interval $[0, 1]$.
A cutpoint is a point that when removed doesn’t leave the remainder still connected, right?
Feb
5
awarded  Yearling
Feb
5
answered Two forms of Beth's theorem?
Jan
18
comment Metrizable group
@jspecter: The quotient of any topological group by a closed normal subgroup is Hausdorff.
Jan
14
comment The roots in a finite field
The criterion for solvability can be written more consisely as $a^{(q-1)/\gcd(m,q-1)}=1$.
Jan
11
awarded  Teacher
Jan
11
answered The roots in a finite field
Dec
19
comment Can we prove the completeness of FOL based on forcing?
It may be worth mentioning that the same construction (considering some more dense sets) can also be used to prove the omitting types theorem. This may help explaining why it only works for countable theories, since unlike the completeness theorem, the omitting types theorem does not hold for uncountable theories.
Dec
19
comment Can we prove the completeness of FOL based on forcing?
As written, the construction does not produce a Henkin theory. $P$ should really be the poset of deductively closed consistent theories extending $T$ which are finitely axiomatized over $T$. Then for every formula $\phi(x)$, the set of conditions forcing $\exists x\,\phi(x)\to\phi(c)$ for some constant $c$ is also dense (due to the countable supply of fresh constants), hence the generic filter will give a Henkin theory.
Oct
30
comment remainder of separable metrizable space
@Brian: Sorry I didn’t notice this earlier, but in your answer, “second-countable $T_4$” and “separable metrizable” are the same thing, one is not more general than the other.
Oct
22
comment remainder of separable metrizable space
@ege: A metrizable space is separable iff it is second countable, and second countability is hereditary.
Apr
5
comment How far do known ordinal notations span?
You can effectively compare ordinals encoded using the same computable well-ordering. You cannot effectively compare two ordinals represented by codes of computable well-orderings, that would be tantamount to making $\omega_1^{CK}$ a computable ordinal, and it would also contradict Rice's theorem.
Mar
2
comment Self-avoiding walk on $\mathbb{Z}$
@DejanGovc: Wrong. The set of such sequences is a Borel (in fact, $G_\delta$) subset of a Polish space, hence it is either countable or of cardinality $2^{\aleph_0}$.
Jan
17
awarded  Supporter