andreas.vitikan
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 Aug13 comment Question about continuous functions and indefinite integrals Ah, it seems that the book wasn't clear enoug. Yes there are functions that satisfy those conditions, but what I was reffering to was that there is no way of expressing it in elementary terms. And isn't $0^0 = 0$ and if not, then I can ask about $[0.5, 1]$ there still isn't an elementary way to express it. Jan14 comment The accumulation points for Dirichlet's function Yes, I think you're right. I'm relatively new to Real Analysis, and english is not my native language (the books are not in english) so sometimes the terms get jumbled up. Jan14 comment The accumulation points for Dirichlet's function Accumulation point, apparently in English they're also called limit points. Jan14 comment The accumulation points for Dirichlet's function Yes, here it is link Jan12 comment I want to study mathematics ahead of high school, but I found that I'm rusty on the elementary stuff Yea, sorry, English is not my first language. What I meant to say is that "For me, personally, they're a bit too slow-paced". Jan11 comment Is this proof about $a^3>a \rightarrow a^5>a$ correct? Yes, you are right. Now that I think of it, it implies that a is different than 0 and $a > -1$. Jan11 comment Is this proof about $a^3>a \rightarrow a^5>a$ correct? Well, when $a = 0$ then simply everything is 0. 0 at any power except 0 is 0. But I don't think that's what they had in mind when they made the exercise and put it in the textbook. Jan11 comment I want to study mathematics ahead of high school, but I found that I'm rusty on the elementary stuff Thanks for the recommendation. As for spending, anything within reason is OK. I could afford, maybe 3 or 4 textbooks like that. Also, free resources are more than welcomed (but from personal experience, good ones are hard as hell to find). In fact, that book looks more or less like what I'm looking for. I'll find a way (maybe look over the old notebooks) to get a proper grip on 5th - 8th algebra, and paired with that book I should be set (it seems to have sequences, trig, functions and the works). And it's for the International Baccalaureate ? Even better then. Jan11 comment Is this proof about $a^3>a \rightarrow a^5>a$ correct? It doesn't even hold for negative a. If we take -2, we get $-8 > -2$ which is obviously false. That's because you're dealing with odd powers (where the sign counts). So, his proof is correct and the fact that $a^3 > a^1$ sort of implies you're dealing with $a \in \mathbb{R}_+$. Jan11 comment I want to study mathematics ahead of high school, but I found that I'm rusty on the elementary stuff The teacher (though I'm not sure of how much to rely on his opinion) said that it's no good, because it's really old, and it's been modified over time in order to match the new curriculum, and now it's a potpourri of stuff, not very useful for learning. From what I've seen, it's quite comprehensive on the theoretical side, but offers almost no exercises and no indication on how to do them. And, even it were good it only covers 9th grade. I need a recap on older stuff, and I also need more advance stuff (trig, and other analysis pre-reqs). Thanks for taking the time to answer. Jan11 comment I want to study mathematics ahead of high school, but I found that I'm rusty on the elementary stuff Thanks for the reply, but I have tried learning from KhanAcademy and I can't. It's just not my style. Either having someone explain it to me face-to-face or using a book, because it's either a faster pace or -in the case of a book- I can set my own pace. However, I could learn the stuff from some other source, ideally written, then do the practice there and maybe even use it as a list of things to go through. So, thanks for the suggestion. Jan10 comment How to solve equations with absolute value and using the Archimedean property Thanks for the comment. I have edited the questions, and hope it is more clear now. Jan10 comment How to solve equations with absolute value and using the Archimedean property So, apply the basic principle that $|x| = a$ then $x = a$ or $x = -a$, but applied to more, right? Jan10 comment How to solve equations with absolute value and using the Archimedean property The absolute value equations I still don't get how to do. $[x/y] \leqslant x/y$ whilst $[x/y] + 1 > x/y$. Also, if I have other questions should I post them in another thread or not?