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location New Jersey, USA
age 48
visits member for 2 years, 11 months
seen Dec 7 at 19:40

Dec
14
awarded  Popular Question
Dec
9
awarded  Tumbleweed
Dec
5
comment Triple Integral to Find Volume
Note: D.A.Robayo's answer probably most advanced answer, but Mike's was the most basic and didn't use skills that haven't been reached in the textbook yet.
Dec
5
accepted Triple Integral to Find Volume
Dec
4
comment Triple Integral to Find Volume
Note: Mathematica and Maple say the answer is $16 \pi$. But I still want to know how to do the integral.
Dec
4
revised Triple Integral to Find Volume
added 2 characters in body
Dec
4
comment Triple Integral to Find Volume
We haven't reached the cylindrical part of the text yet.
Dec
4
comment Triple Integral to Find Volume
@D.A.Robayo I put the wrong word when I copied the question. I fixed the post. They want the volume of the solid enclosed by the parabaloids. My bad.
Dec
4
revised Triple Integral to Find Volume
deleted 15 characters in body
Dec
4
revised Triple Integral to Find Volume
deleted 2 characters in body
Dec
4
asked Triple Integral to Find Volume
Dec
2
asked Question about the projection of a 3-d region onto the $xz$-plane
Nov
18
comment Prove: if dot product is constant, then vector dot its derivative is zero.
Well, that was easy. :)
Nov
18
accepted Prove: if dot product is constant, then vector dot its derivative is zero.
Nov
18
asked Prove: if dot product is constant, then vector dot its derivative is zero.
Aug
26
comment Prove triangles formed by two midpoints and an altitude are congruent
Can you explain how BP=PH? I don't see how the intercept theorem applys. We can only use congruent triangle parallel line theorems.
Aug
26
comment Prove triangle made from two altitudes and midpoint is isosceles
Did that. I can see that $\angle HEF = \angle MEB$ (vertical angles) and that $\angle HFE = \angle EMB$ (alternate interior angles). But I do not see how to equate two sides of the triangles to prove congruence.
Aug
26
comment Prove triangles formed by two midpoints and an altitude are congruent
I think that's only true if you've already established that $MN || AC$. But I've found that can be established using a parallelogram with side $CE$ parallel to $AM$.
Aug
26
comment Prove triangle made from two altitudes and midpoint is isosceles
Good answer. Can you clarify a little how we know that E is the midpoint of HB?
Aug
26
accepted Prove triangle made from two altitudes and midpoint is isosceles