David Ward
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 Feb10 comment Find value of K? So what have you learnt about choosing things? Also, have you tried working out how many ways there would be of selecting $K$ coupons if $K=1,2,3,4$? Feb10 comment Find value of K? What have you tried so far? Jan6 awarded Yearling Aug6 awarded Popular Question Jul2 awarded Curious Feb12 comment Character Table of the Monster Excellent, thanks for that. Feb12 accepted Character Table of the Monster Feb12 comment Character Table of the Monster Sorry, I probably should extrapolate a tiny bit, I need to do calculations with it involving the entries for elements of order 2, hence only need the character degrees and the values for 2A and 2B, but don't really want to enter these manually from the Atlas! Feb12 asked Character Table of the Monster Jan31 revised Order of a permutation using its cycle decomposition Added tags permutations and finite-groups Jan31 suggested approved edit on Order of a permutation using its cycle decomposition Jan6 awarded Yearling Jan3 comment Coercing a vector into a module in MAGMA. So if for example I was working with the 2-dimensional irreducible module for $Sym(4)$ over $\mathbb{F}_{2}$ - just to keep things really simple, then I might have the matrix $A:=[0 1]$ over $\mathbb{F}_{2}$ that I want to treat as an element of $I$. Using the coercion mentioned in the question I would need to use $I![0,1]$ whereas to use the other method, I would need to use $elt$. Is there any way of doing this just by calling on $A$? (I hope that makes sense, but using MAGMA is not my strong point!) Jan3 comment Coercing a vector into a module in MAGMA. So an obvious way to do this is to form the appropriate sum of basis elements, but I suppose my question is whether or not there is a command already built into MAGMA that will do this. Jan3 comment Coercing a vector into a module in MAGMA. Yest, $M$ is the $n$-dimensional $R$-module. Jan3 asked Coercing a vector into a module in MAGMA. Dec27 accepted Producing a set of matrices in MAGMA Dec27 revised Intuition and Tricks - Hard Overcomplex Proof - Order of Subgroup of Cyclic Subgroup - Fraleigh p. 64 Theorem 6.14 added finite-groups and cyclic-groups tags Dec27 suggested approved edit on Intuition and Tricks - Hard Overcomplex Proof - Order of Subgroup of Cyclic Subgroup - Fraleigh p. 64 Theorem 6.14 Dec27 answered Intuition and Tricks - Hard Overcomplex Proof - Order of Subgroup of Cyclic Subgroup - Fraleigh p. 64 Theorem 6.14