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Jun
14
accepted Vitali set of outer-measure exactly $1$.
Jun
13
comment Normal, Non-Metrizable Spaces
@ChrisEagle: I guess it depends how you define normal. Some include Hausdorff in the definition.
Jun
13
comment Vitali set of outer-measure exactly $1$.
@AsafKaragila: Thanks for the help, I will do that.
Jun
13
revised Basic fact in $L^p$ space
added 31 characters in body
Jun
13
answered Basic fact in $L^p$ space
Jun
13
comment Basic fact in $L^p$ space
What role does $q$ play?
Jun
13
comment Basic fact in $L^p$ space
Which one is the basic fact and what fact are you trying to prove?
Jun
13
comment Vitali set of outer-measure exactly $1$.
@AsafKaragila: Thanks. Do you have some references for this where I could possibly look it up?
Jun
13
comment Vitali set of outer-measure exactly $1$.
@GiuseppeVitali: Do you know if anyone has gone through the details of this construction and checked whether it works and gives the desired set?
Jun
12
comment Collection of converging sequences determines the topology?
No problem. There is still one $X$ left though :-)
Jun
12
comment Collection of converging sequences determines the topology?
@BrianM.Scott: You define $\tau_{2}$ by using the notion of $X$ and $D$ simultaneously. That is the reason why I'm asking.
Jun
12
comment Collection of converging sequences determines the topology?
What role does $X$ play in the above construction. Is $D\subset X$?
Jun
12
revised Collection of converging sequences determines the topology?
added TeX.
Jun
12
suggested approved edit on Collection of converging sequences determines the topology?
Jun
12
comment Vitali set of outer-measure exactly $1$.
The person who down-voted is welcome to leave a comment and explain why so.
Jun
12
asked Vitali set of outer-measure exactly $1$.
Jun
12
revised Interior, exterior and boundary of sets in $\mathbb R^2$
added 10 characters in body
Jun
12
comment Interior, exterior and boundary of sets in $\mathbb R^2$
Your answer on $B$ is not correct.
Jun
12
answered Interior, exterior and boundary of sets in $\mathbb R^2$
Jun
12
comment Limits of Subsequences
With the same idea it actually follows that for any subsequence of $\{t_{n}\}$ we find such a subsequence of $\{s_{n}\}$ that decreases more rapidly. And I don't think we needed the fact that $s_{n}\leq t_{n}$ at all.