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Nov
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accepted $n$-words over the alphabet $\{0,…,d\}$ without consecutive $0$'s
Nov
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revised $n$-words over the alphabet $\{0,…,d\}$ without consecutive $0$'s
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Nov
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reviewed Approve Showing that $\sum{x^k}$ does not converge uniformly on $(-1,1)$
Nov
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reviewed Approve If $A^2 = I$, then $A$ is diagonalizable, and is $I$ if $1$ is its only eigenvalue
Nov
6
comment $n$-words over the alphabet $\{0,…,d\}$ without consecutive $0$'s
But $\sum_{\geq 1} f(n)x^n=\frac{3x+2x^2}{1-2x-2x^2}$, not what you claimed. If you expand your generating function, you see it only agrees with the first two terms.
Nov
6
revised $n$-words over the alphabet $\{0,…,d\}$ without consecutive $0$'s
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Nov
5
awarded  Notable Question
Nov
5
asked $n$-words over the alphabet $\{0,…,d\}$ without consecutive $0$'s
Sep
13
comment Identity involving Stirling numbers of second kind $S(n,k)$ and $k$-compositions of $n$
Thanks for the solution. I didn't even think about the generating function of $S(n,k)$. Once you know that, the problem falls into place.
Sep
13
accepted Identity involving Stirling numbers of second kind $S(n,k)$ and $k$-compositions of $n$
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12
revised Identity involving Stirling numbers of second kind $S(n,k)$ and $k$-compositions of $n$
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Sep
12
asked Identity involving Stirling numbers of second kind $S(n,k)$ and $k$-compositions of $n$
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25
comment How do I approach this combinatorics problem about firing order in an engine?
I believe the answer is $2\cdot n!^2$, as one must first decide whether to start with an even or an odd number.
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10
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