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Jul
14
comment Fourier transforms of $f(t)=\frac{\sin{at}}{t}$
+1 very nice answer. You wrote all steps in clear way.
Jul
13
comment Is $ \sum_{n=-\infty}^\infty x^n=0 $?
I updated my question . Can there be any connection with Ramanujan’s mysterious expression about infinity sum of numbers with my infinity sum result? . It was strange in the begining before checking the result for extention zeta function
Jun
3
comment How to find minimum distance path between 2 points on a surface
@mathreadler Thanks a lot for your comment. I try to find out theoretical solution for exact shortest path equation via calculus. I know we can do many things via computer algorithms but I am not interested in that way.
Jun
2
comment How to find minimum distance path between 2 points on a surface
We cannot use it here. Because $t_1$ and $t_2$ fixed points. Please check the link I gave.
May
29
comment Tangent points on circle that placed on Earth surface
@user86418 That's right. but please think that it is not a unit sphere .It has radius $R$
Apr
20
comment Compute $\int _{\frac{4}{5}}^2\:f^{-1}\left(x\right)dx$
Yes İt could be .Thanks for comment. I just wanted to give a hint how to approach for such problems.
Apr
20
comment Binomial Theorem of Differentiation?
You are welcome.
Apr
20
comment Binomial Theorem of Differentiation?
Yes . It will work you can use that method to prove the multinational but it will has longer terms. You may try to find the coefficients of $e^{xh}e^{yh}e^{zh}=e^{(x+y+z)h}$. Good luck
Apr
3
comment Is there a formula for $\sum_{n=0}^{+\infty} q^{n^3}$?
Have you seen my question on the subject? I will be appreciated if you check.math.stackexchange.com/questions/358407/… Thanks
Apr
3
comment To evaluate $\int_0^{+\infty} \frac{\;\mathrm dx}{\sqrt[3]{x^3+a^3}\sqrt[3]{x^3+b^3}\sqrt[3]{x^3+c^3}}$
@Noam D. Elkis I think that you mistyped $x^3 = 1/t$, $dx = -t^{-2/3} dt/3$ . I have updated it as $dx = -t^{-4/3} dt/3$ . Thanks a lot for your great answer.
Feb
12
comment General solution to ODE $ y''-Ay^5=0 $
You can use the same way as I showed for other similiar question.math.stackexchange.com/questions/166981/…
Nov
14
comment Analysis of the function $\prod_{n=-\infty}^{ \infty }(1-e^{-a{(x+n)^2} })$
@AleksVlasev Could you please give more detail? Thanks
Nov
13
comment Analysis of the function $\prod_{n=-\infty}^{ \infty }(1-e^{-a{(x+n)^2} })$
@sonystarmap Wonderful result. Exactly As I expected in theory. I wonder if the function can be expressed as f(x)=A(a)sin2πx or not. I mean if G(x,a) does not to depend on x . I try to prove or disprove it now. Maybe you can help me via Matlab codes draw G(x,a).Is it possible depends on only a ? Thanks a lot
Nov
13
comment Analysis of the function $\prod_{n=-\infty}^{ \infty }(1-e^{-a{(x+n)^2} })$
@sonystarmap Thanks a lot.
Nov
4
comment To find the general formula of $\overbrace{g(g(g(…g(x))}^\text{n}=g_n(x)=\frac{A_{n}.x+B_{n}}{C_{n}.x+D_{n}}$
I understood that how to get matrix result. I had applied in my question. I will try to get result via eigenvalues . Thanks
Nov
4
comment To find the general formula of $\overbrace{g(g(g(…g(x))}^\text{n}=g_n(x)=\frac{A_{n}.x+B_{n}}{C_{n}.x+D_{n}}$
how can that relation be proved? Please advice a method.
Nov
4
comment To find the general formula of $\overbrace{g(g(g(…g(x))}^\text{n}=g_n(x)=\frac{A_{n}.x+B_{n}}{C_{n}.x+D_{n}}$
It is very nice. I wonder something if it is possible to express $A_n,B_n,C_n,D_n $ as exponential functions as we can do for $F_n$ or not?
Oct
13
comment How to find sum of coefficients of $\frac{d^n}{dx^n} \left( Z(x)^m \right)$
Really nice approach: I liked the way you used $Z(x)=e^x$ in $U$ Function . It made very easy proof and also thanks for generalized formula.
Oct
10
comment How to find sum of coefficients of $\frac{d^n}{dx^n} \left( Z(x)^m \right)$
@marco trevi: It is the function that depends on x
Aug
14
comment How to express $e^{yS^2}(f(x))$ in closed form where $\frac{d}{dx}=S$
@Winther Thanks a lot for comments. The final expression is very beautiful. I will focus on some examples to confirm .It can be used as a nice tool.