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I am an engineer who is in love with math and lifelong math student. I love to learn new things in mathematics for self-satisfaction. My idols are Gauss , Euler , Ramanujan because they were in love with math as I feel.


Nov
13
answered Parameterizing an ellipse
Nov
13
revised Analysis of the function $\prod\limits_{n=-\infty}^{ \infty }(1-e^{-a{(x+n)^2} })$
added 2 characters in body
Nov
11
revised Analysis of the function $\prod\limits_{n=-\infty}^{ \infty }(1-e^{-a{(x+n)^2} })$
edited title
Nov
11
revised Analysis of the function $\prod\limits_{n=-\infty}^{ \infty }(1-e^{-a{(x+n)^2} })$
added 1436 characters in body; edited title
Nov
10
revised Analysis of the function $\prod\limits_{n=-\infty}^{ \infty }(1-e^{-a{(x+n)^2} })$
added 2 characters in body
Nov
10
asked Analysis of the function $\prod\limits_{n=-\infty}^{ \infty }(1-e^{-a{(x+n)^2} })$
Nov
4
comment To find the general formula of $\overbrace{g(g(g(…g(x))}^\text{n}=g_n(x)=\frac{A_{n}.x+B_{n}}{C_{n}.x+D_{n}}$
I understood that how to get matrix result. I had applied in my question. I will try to get result via eigenvalues . Thanks
Nov
4
comment To find the general formula of $\overbrace{g(g(g(…g(x))}^\text{n}=g_n(x)=\frac{A_{n}.x+B_{n}}{C_{n}.x+D_{n}}$
how can that relation be proved? Please advice a method.
Nov
4
revised To find the general formula of $\overbrace{g(g(g(…g(x))}^\text{n}=g_n(x)=\frac{A_{n}.x+B_{n}}{C_{n}.x+D_{n}}$
edited body
Nov
4
comment To find the general formula of $\overbrace{g(g(g(…g(x))}^\text{n}=g_n(x)=\frac{A_{n}.x+B_{n}}{C_{n}.x+D_{n}}$
It is very nice. I wonder something if it is possible to express $A_n,B_n,C_n,D_n $ as exponential functions as we can do for $F_n$ or not?
Nov
4
revised To find the general formula of $\overbrace{g(g(g(…g(x))}^\text{n}=g_n(x)=\frac{A_{n}.x+B_{n}}{C_{n}.x+D_{n}}$
added 153 characters in body
Nov
4
asked To find the general formula of $\overbrace{g(g(g(…g(x))}^\text{n}=g_n(x)=\frac{A_{n}.x+B_{n}}{C_{n}.x+D_{n}}$
Oct
20
awarded  Popular Question
Oct
13
accepted How to find sum of coefficients of $\frac{d^n}{dx^n} \left( Z(x)^m \right)$
Oct
13
comment How to find sum of coefficients of $\frac{d^n}{dx^n} \left( Z(x)^m \right)$
Really nice approach: I liked the way you used $Z(x)=e^x$ in $U$ Function . It made very easy proof and also thanks for generalized formula.
Oct
13
answered How to find sum of coefficients of $\frac{d^n}{dx^n} \left( Z(x)^m \right)$
Oct
10
revised How to find sum of coefficients of $\frac{d^n}{dx^n} \left( Z(x)^m \right)$
added 549 characters in body
Oct
10
comment How to find sum of coefficients of $\frac{d^n}{dx^n} \left( Z(x)^m \right)$
@marco trevi: It is the function that depends on x
Oct
10
revised How to find sum of coefficients of $\frac{d^n}{dx^n} \left( Z(x)^m \right)$
added 78 characters in body; edited title
Oct
10
asked How to find sum of coefficients of $\frac{d^n}{dx^n} \left( Z(x)^m \right)$