breezeintopl
Reputation
528
Top tag
Next privilege 1,000 Rep.
Create new tags
 Apr 29 asked integration with singular continuous measure in high(two) dimensions Apr 26 asked integration with delta function Mar 27 comment positive definite of a matrix(diagonal decay) Hi @JackD'Aurizio, thanks for your insightful comment! Could you please elaborate a little bit about why you want to use this theorem? Is it a tool to bound the eigenvalues of the above matrix? What it the projection matrix $P$ in this case? Mar 27 asked characteristic polynomial of linear combination of two matrices Mar 27 comment positive definite of a matrix(diagonal decay) BTW, how did you find the determinant(so quickly)? from the above row/column operation to upper/lower triangular matrix? Thanks! Mar 27 accepted positive definite of a matrix(diagonal decay) Mar 27 comment positive definite of a matrix(diagonal decay) Thanks! This decomposition is interesting and I think it may help for further analysis the properties of this matrix. Mar 27 comment positive definite of a matrix(diagonal decay) OK, so then only preserve determinant(product of eigenvalues). Does it preserve the sign of eigenvalues? Seems I need to check my linear algebra textbook once more... Mar 27 comment positive definite of a matrix(diagonal decay) Seems true. It preserves determinant and similarity(but not char. poly.), right? Mar 27 comment positive definite of a matrix(diagonal decay) Thanks. This solves the problem(and can help find the determinant). Mar 27 comment positive definite of a matrix(diagonal decay) Thanks! This solves the problem! Mar 27 asked positive definite of a matrix(diagonal decay) Mar 14 awarded Notable Question Oct 28 comment Covariance, covariance operator, and covariance function Do you mean that $E[ ]: H^*\to R$ is a functional on $H^*$, so it is in $H^{**}$. And $H^{**}=H$. So then $E[]$, as element in $H^{**}$ be represented by m in $H^*$, so then $E[\phi]=<\phi,m>_{H^*}=\phi(m)=$? Oct 28 comment Covariance, covariance operator, and covariance function I mean, why "the mean can be represented by an element in H"? I don't understand this. "A real number(the mean) can be represented by an element in Hilbert space"? (I mean, by Riesz, functional on H can be represented. why here the mean can also be represented?) Oct 28 comment Covariance, covariance operator, and covariance function Thank you for your answer! One question about the concept: is the result of the expectation in $R$ or in $X$ or in $X^*$? Is this the same as the mean map or the distribution embedding to RKHS? Sep 29 awarded Popular Question Apr 14 comment find special basis to make null space part equal to zero Thank you so much for your answer! Apr 7 accepted Computing bases for direct, wedge, tensor products, etc., of given vector spaces Apr 7 revised Computing bases for direct, wedge, tensor products, etc., of given vector spaces added 16 characters in body