7,905 reputation
1636
bio website
location Kathmandu, Nepal
age
visits member for 4 years, 2 months
seen 50 mins ago

Now just another ordinary stupid NEET. Abstract Algebra has always been my enemy, now I am trying to conquer it.


1d
reviewed Reject suggested edit on Prove that if $ac$ has a square root modulo $p$ and if…
1d
awarded  Notable Question
Nov
23
answered Does $\sum_{n \ge 2}{(n\log^2(n))^{-1}}$ converge?
Nov
4
comment Convergence of infinite series$ \frac{(\ln(n))^2}{n^2}$
for some $N \in \Bbb N $, $ \log(n) < n^{1/4}$ for all $n\ge N$
Oct
22
awarded  Notable Question
Oct
19
comment Examining the convergence of $\int_{1}^{\infty}\frac{1}{x^2+x}\text{ d}x$
how about $$\int_1^\infty \frac 1 x dx - \int_1^\infty \frac 1 {x+1} dx=\int_1^2 \frac 1 x dx +\int_1^\infty \frac 1 {x+1} dx- \int_1^\infty \frac 1 {x+1} dx$$
Oct
4
comment Answer difference of same series with different index
because of the index since it starts with zero while other starts with 1 ... on second series you get extra $3$
Sep
30
awarded  Explainer
Sep
29
awarded  Yearling
Aug
2
revised Calculate $\int \log(1+\log(x))x^ndx$
latex
Jul
15
revised Help with this limit
latex
Jul
12
awarded  Good Question
Jul
11
comment How find this limit $I=\lim_{n\to\infty}\sum_{k=0}^{n}\frac{\cos{\sqrt{\frac{k}{n}}}}{2^k}$
isn't $I \le 2$ ??
Jul
8
comment Evaluation of $\int\sqrt[4]{\tan x}dx$
I get this very long and nasty expression from Wolf
Jul
2
awarded  Curious
Jun
29
revised Method for evaluating $\int_{|z| = 1} \dfrac{z^2}{\sqrt[4]{P(z)}} dz$
edited tags
Jun
27
comment Geometric interpretation of a Taylor series like identity
you probably mean $f(0)$, BTW doesn't the interpretation work??
Jun
25
comment Where does this unit vector come from?
also check this link i.stack.imgur.com/13R5J.png
Jun
25
comment Where does this unit vector come from?
scroll this link a bit upwards ... use $r=1$ and as for $y$ note the direction.
Jun
25
comment Where does this unit vector come from?
given that you know the magnitude of vector and two angles (azimuthal and polar), you can decompose the vector into x, y and z components ... which is what you get as above.