276 reputation
114
bio website ziga-lausegger.netau.net/…
location Slovenia
age 28
visits member for 2 years, 7 months
seen Nov 26 '13 at 13:11

I love to program and crosscompile baremetal C programs for ARM based microcontrollers, I love physics and i love writing science documents/books in LaTeX. It amazes me how physics is connecting all science and is helping mathematics to evolve. In order for science profession to comunicate on a high level i advise everyone to use Linux, LaTeX and a good vector imaging program like Inkscape.


May
12
comment Weird Identities with Scalar Product & Transpose: $\vec{a}\cdot\vec{b} = \vec{b}^T \cdot {a}^T$, $\vec{a}^T \cdot \vec{b} = \vec{b}^T \cdot \vec{a} $?
Ok so what you wanted is to warn me that in TEXT i have to be careful how to talk about vectors and matrix. If i have for example: $$a=\begin{pmatrix}1&2&3\end{pmatrix}\qquad \vec{b}=\begin{pmatrix}4\\5\\6\end{pmatrix}$$ i can say in text that $b$ is a vector, but i can't say this for $a$ which is only a matrix $1\times 3$. But i can read in en.wikipedia.org/wiki/Matrix_multiplication that: "Treating the rows and columns in each matrix as row and column vectors respectively, this entry is also their vector dot product"?
May
12
comment Weird Identities with Scalar Product & Transpose: $\vec{a}\cdot\vec{b} = \vec{b}^T \cdot {a}^T$, $\vec{a}^T \cdot \vec{b} = \vec{b}^T \cdot \vec{a} $?
Can you check also my edit please.
May
12
revised Weird Identities with Scalar Product & Transpose: $\vec{a}\cdot\vec{b} = \vec{b}^T \cdot {a}^T$, $\vec{a}^T \cdot \vec{b} = \vec{b}^T \cdot \vec{a} $?
added 999 characters in body
May
12
comment Weird Identities with Scalar Product & Transpose: $\vec{a}\cdot\vec{b} = \vec{b}^T \cdot {a}^T$, $\vec{a}^T \cdot \vec{b} = \vec{b}^T \cdot \vec{a} $?
I don't understand what you are trying to say. @Alfonso Fernandez says i did it ok. Can you please try to explain it on an example?
May
12
comment Weird Identities with Scalar Product & Transpose: $\vec{a}\cdot\vec{b} = \vec{b}^T \cdot {a}^T$, $\vec{a}^T \cdot \vec{b} = \vec{b}^T \cdot \vec{a} $?
At the moment only unclarity to me is what @Samuel wrote. I don't get it.
May
12
asked Weird Identities with Scalar Product & Transpose: $\vec{a}\cdot\vec{b} = \vec{b}^T \cdot {a}^T$, $\vec{a}^T \cdot \vec{b} = \vec{b}^T \cdot \vec{a} $?
May
12
comment I need a proof for a scalar product - no numbers allowed
Could you post a bit more. How can you get $\mathbf{a} \cdot \mathbf{b} = a_1b_1 + a_2 b_2$ out of your post ???
May
11
accepted I need a proof for a scalar product - no numbers allowed
May
11
asked I need a proof for a scalar product - no numbers allowed
May
11
comment Complex numbers and absolute values
But it could allso be real right?
May
11
comment Complex numbers and absolute values
But there is a possibility that $\psi$ is complex?
May
11
accepted Complex numbers and absolute values
May
11
comment Complex numbers and absolute values
This means $\left|\psi\right|$ is always real and $\psi$ complex? Can you please edit your anwser and show me how you got equation $\left|\psi\right|=\sqrt{\alpha^2+\beta^2}$.
May
11
asked Complex numbers and absolute values
May
8
awarded  Tumbleweed
May
5
asked Complex 3-D Euclidean space - inner product
May
4
accepted Differential equation with no constants.
Apr
29
asked Differential equation with no constants.
Apr
25
comment Solving a system of four equations
Yes they vary in $\mathbb{R}$ and i used matrices, because i know that my system can be written in a matrix form (check my edit).
Apr
25
revised Solving a system of four equations
added 439 characters in body