1,143 reputation
1619
bio website
location
age
visits member for 2 years, 9 months
seen 1 hour ago

Sep
14
comment Does the following integral converge: $\int_6^{\infty}\frac{dx}{\sqrt{1+x^2}}$
Why won't you just evaluate it?
Sep
13
comment Analysis of the function $y=x^{\frac{1}{x}}$
@ClaudeLeibovici I plotted $\Im x^{1/x}$ in Mathematica, it's not zero for $(-1,0)$.
Sep
13
comment Analysis of the function $y=x^{\frac{1}{x}}$
It's complex valued for $x\le0$.
Sep
7
comment Recurrence relation of the following sequence?
It's simply only the $a_n = \lceil\frac{n}{2}\rceil$. Why even-odd?
Aug
26
comment How to prove $\int^{\pi/2}_0 \log{\cos{x}} \, \mathrm{d}x = \pi/2 \log{1/2}$
@idm this can be easily integrated by parts.
Aug
25
comment How do I integrate $\frac{\sqrt{1-k^2\sin^2 x}}{\sin x}$
@Jean-ClaudeArbaut Thanks for this reference. Why'd in physics I didn't encounter the one's, that can be expressed with elementary functions?
Aug
25
comment How do I integrate $\frac{\sqrt{1-k^2\sin^2 x}}{\sin x}$
@Jean-ClaudeArbaut Maybe, as a physicist mine elliptic integrals are one, two, three complete/incomplete integrals.
Aug
25
comment How do I integrate $\frac{\sqrt{1-k^2\sin^2 x}}{\sin x}$
@Jean-ClaudeArbaut It's definitely not an elliptic integral. It's actually can be expressed as a primitive functions.
Aug
24
comment Quotient rule, one sign wrong
@Paul Nope, you are correct, and the book answer is wrong.
Aug
24
comment Why is the result of $-2^2 = -4$ but $(-2)^2 =4$?
Because first one is $-(2^2) = -(2\cdot 2) = -4$ and the second one is $(-2)^2 = (-2)\cdot(-2) = 4$?
Aug
23
comment How to solve this linear system using determinants and using matrices
Move the $3y$ to the LHS in that equation... and be happy!
Aug
22
comment How to find $\int \frac{x^4-4}{x^2\sqrt{4+x^2+x^4}} \,\mathrm dx$
@Aditya and what is the solution in textbook?
Aug
22
comment What is the concept behind …?
Concept of vector calculus.
Aug
22
comment Integral of inverse of square root of a quadratic
@Starior Because there are infinitely, but uncountable set of rings; and sum can only been used on a countable set of rings.
Aug
21
comment calculus / algebra
Is this from some physics textbook? Share the context.
Aug
21
comment Integral of inverse of square root of a quadratic
@Starior Yes. I used $+\delta$.
Aug
21
comment Integral of inverse of square root of a quadratic
@Starior I used the cylindric coordinates, where $z$ is a line of symmetric of this rings.
Aug
21
comment Integral of inverse of square root of a quadratic
@Starior Use Gauss law for this.
Aug
21
comment Integral of inverse of square root of a quadratic
@Starior Provide a physical context of problem. That would be more useful than the pointless $a$, $b$, $c$, $g$ and $q$.
Aug
21
comment Integral of inverse of square root of a quadratic
What's that? Replace $c$ by $g$, than you need to only integrate a constant. The question is malformed, btw.