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| bio | website | |
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| age | ||
| visits | member for | 1 year, 5 months |
| seen | May 16 at 12:02 | |
| stats | profile views | 52 |
Discipulus sum in Iaponia.
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May 16 |
accepted | On the eigenvalues of a linear transformation $\tau$ such that $\tau^3 = \mathrm{id}$ |
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May 15 |
comment |
On the eigenvalues of a linear transformation $\tau$ such that $\tau^3 = \mathrm{id}$ My mother tongue not being English, I thought the word "all" in the phrase "whose eivenvalues are of course all powers of a cube root of unity" modifies "powers", not "eigenvalues" :-( Regarding the mathematical content of the issue, is there a counterexample of such $\tau$ that not all of the powers of $\omega$ are its eignevalues? |
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May 15 |
comment |
On the eigenvalues of a linear transformation $\tau$ such that $\tau^3 = \mathrm{id}$ Seems like this question really belongs to english.stackexchange.com ... |
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May 15 |
asked | On the eigenvalues of a linear transformation $\tau$ such that $\tau^3 = \mathrm{id}$ |
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May 14 |
accepted | On the proof of Schur's lemma in Fulton & Harris |
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May 14 |
comment |
On the proof of Schur's lemma in Fulton & Harris I've totally forgotten that the two spaces are irreducible :-( |
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May 14 |
asked | On the proof of Schur's lemma in Fulton & Harris |
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May 12 |
accepted | Reference request: Newton-Kantorovich hypothesis for polynomials of integral coefficients |
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May 12 |
awarded | Benefactor |
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May 6 |
comment |
Reference request: Newton-Kantorovich hypothesis for polynomials of integral coefficients Thank you. What I really wanted to see was the particular application of the Newton method to polynomials of integral coefficients. (Please let me know if one of these articles contains the application, just in case I overlooked it.) |
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May 5 |
awarded | Promoter |
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May 5 |
revised |
Reference request: Newton-Kantorovich hypothesis for polynomials of integral coefficients added 3 characters in body |
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May 4 |
comment |
How to enumerate subgroups of each order of $S_4$ by hand In my original problem, I understand that you calculated the index of the normalizer or found the parameterized general form of subgroups and counted the parameters, to obtain the number of subgroups of a specific type. Is this correct? |
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May 4 |
accepted | How to enumerate subgroups of each order of $S_4$ by hand |
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May 4 |
comment |
How to enumerate subgroups of each order of $S_4$ by hand Thank you for your helpful answer. What do you think is the easiest way, in general, to determine of what form the element of a subgroup of a specific type (conjugacy class or isomorphic class) is, and how many subgroups fall in that type? |
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May 3 |
comment |
How to enumerate subgroups of each order of $S_4$ by hand @amWhy I would be most grateful if you could tell me what part of the answer to the old question answers my question. |
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May 3 |
revised |
How to enumerate subgroups of each order of $S_4$ by hand added 139 characters in body |
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May 3 |
comment |
How to enumerate subgroups of each order of $S_4$ by hand @zach How do you find the isomorphism types of the subgroups given a finite (symmetric) group? |
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May 3 |
asked | How to enumerate subgroups of each order of $S_4$ by hand |
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May 3 |
asked | Reference request: Newton-Kantorovich hypothesis for polynomials of integral coefficients |
